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3 years ago

I need help with this problem, please

Mathematics

1 answer:

raketka [301]3 years ago

7 0

Answer:

option 2

Step-by-step explanation:

Let equation for this table be y = mx + c, where m is the gradient (or slope) and c is the y intercept (or constant term)

m = (-4-(-2))/(7-5)

= -1

sub m = -1 and x = 1 and y = 2:

2 = -1(1) + c

c = 3

therefore, equation: y = -x + 3

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3 years ago

The triangle and rectangle

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3 years ago

determine whether the lines intersect and if so find the point of intersection and the cosine of the angle of intersection x=4t+

Fittoniya [83]

Answer:

As the lines are not intersecting nor parallel, they must be skew.

Step-by-step explanation:

Question is incomplete, we consider the nearest match available online.

Parametric equations of two lines are:

L₁ : x=4t+2 , y = 3 , z =-t+1

L₂: x=2s+2 , y= 2s+5 , z = s+1

If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.

$4t+2=2s+2 ---(1)\\ \\3=2s+5---(2) \\\\-t+1=s+1---(3)$

If lines are intersecting then parametric coordinates must be equal for some value of t and s.

$From (3)\\-t=s\\From (2)\\\\s=\frac{3-5}{2}\\\\s=-1\\\implies t=1\\\\To\,\,check\,\, the \,\,values \,\,of \,\,s\,\, and \,\,t \,\,for\,\,intersection\,\,put \,\,them\,\, in\,\, (1)\\\\4(1)+2= 2(-1)+2\\ 6\ne0$

Hence the lines are not intersecting nor parallel, they must be skew.

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3 years ago

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D

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2 years ago

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navik [9.2K]

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Step-by-step explanation:

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3 years ago

I need help with this problem, please ​

I need help with this problem, please