9514 1404 393
Answer:
- Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
- Objective formula: p = 45x +50y
- 200 YuuMi and 50 ZBox should be stocked
- maximum profit is $11,500
Step-by-step explanation:
Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...
250x +400y ≤ 70000
The number sold will be at most 250 units, so that constraint is ...
x + y ≤ 250
Additionally, we require x ≥ 0 and y ≥ 0.
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A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...
profit = 45x +50y
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A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).
200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.
7abc and 8abc-8 are the answers.
Answer:
y=2x-3
Step-by-step explanation:
The slope-intercept form of the original equation would be y=3/8−x/2
Therefore, the slope of the perpendicular line would be m=2
Then, the y-intercept would be 7=(2)x(5)+a
A=-3
Answer:
y=2x+3
S = 10 + r
s + r = 100
Adding equations,
2s +r = 110 + r
2s = 110
s = 55
r = 45
9514 1404 393
Answer:
a = 9 meters
Step-by-step explanation:
The perimeter is the sum of the side lengths:
28 m = a + 2m + a + 8m
18 m = 2a . . . . . . . . . . . . . . . . subtract 10m, collect terms
9 m = a . . . . . . . . . . . . . . . divide by 2
The value of a is 9 meters.