Answer:
Step-by-step explanation:
5x+3y=1
4x-5y=4
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4(5x+3y)=4(1)
-5(4x-5y)=-5(4)
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20x+12y=4
-20x+25y=-20
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37y=-16
y=-16/37
5x+3(-16/37)=1
5x-48/37=1
5x=1+48/37
5x=37/37+48/37
5x=85/37
x=(85/37)/5
x=(85/37)(1/5)
x=85/185
x=17/37
Answer: x=17/37, y=-16/37. (17/37, -16/37)
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5x+3y=1
8x-10y=4
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8(5x+3y)=8(1)
-5(8x-10y)=-5(4)
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40x+24y=8
-40x+50y=-20
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75y=-12
y=-12/75=-4/25
5x+3(-4/25)=1
5x-12/25=1
5x=1+12/25
5x=25/25+12/25
5x=37/25
x=(37/25)/5
x=(37/25)(1/5)
x=37/125
Answer: x=37/125, y=-4/25. (37/125, -4/25).
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5x+3y=1
9x-2y=5
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2(5x+3y)=2(1)
3(9x-2y)=3(5)
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10x+6y=2
27x-6y=15
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37x=17
x=17/37
5(17/37)+3y=1
85/37+3y=1
3y=1-85/37
3y=37/37-85/37
3y=-48/37
y=(-48/37)/3
y=(-48/37)(1/3)
y=-48/111
Answer: x=17/37, y=-48/111. (17/37, -48/111).
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We have that
x²+2xy+4y²<span>=12
we know that
</span>A better way to do this problem is using what is called “Implicit Differentiation
so
step 1
Differentiate both sides of the equation using the Chain Rule
x²+2xy+4y²=12-------> 2x+2y+2xy1+8yy1=0
2xy1+8yy1=-2x-2y--------> y1*[2x+8y]=-2x-2y
y1=(-2x-2y)/(2x+8y)
for the point (2,1)
y1=(-2*2-2*1)/(2*2+8*1)-------> y1=-6/12------> y1=-1/2
step 2
find the equation <span>of the tangent line with m=-1/2 and the point (2,1)
y-y0=m*(x-x0)------> </span>y-1=(-1/2)*(x-2)-----> y-1=(-1/2)x+1
y=(-1/2)x+2
the answer isy=(-1/2)x+2using a graph tool
see the attached figure
Answer:
Send q picture of the graphs so I can help
Step-by-step explanation:
need pictures of graph
Add up all the numbers and then divide it by how many number are in the set. so you would add it all up and divide by nine
Answer: 1/2
Step-by-step explanation:
f(x) = A sin (Bx - C) + D
amplitude = |A|
period =
phase shift =
vertical shift = D
A
amplitude of 3 is given so 3 = |A| → A = ± 3, since it is stated that this is a positive function, then A = 3
B
period of 6π is given so
C
D
vertical shift of -1 is given so -1 = D
Now, substitute the values of A, B, C, and D into the formula (above):
Next, solve when x = 2π