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vlada-n [284]
1 year ago
7

Simplify (sqrt)98m^12 using factor tree or splitting up using perfect squares. Quick answer showing work = amazing review :)

Mathematics
1 answer:
strojnjashka [21]1 year ago
6 0

The expression is:

\sqrt[]{98m^{12}}

We need to use a factor tree to solve the problem. We will draw it as shown below:

According to the factor tree we can represent the 98 as:

\sqrt[]{2\cdot7^2m^{12}}

We can now remove the terms that have a power of 2 and a power of 12. For that we need to divide the exponents by 2.

7^{}\sqrt[]{2}m^6

The simplified expression is 7*sqrt(2)*m^6.

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Simplify y 2 + 11y - 6y + y 2​
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Answer:

y2+5y+2

Step-by-step explanation:

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A ______ involves both an experimental group and a control group, which are alike except for the one viable that the experiment
konstantin123 [22]

Answer:

controlled experiment

Step-by-step explanation:

Controlled experiment is a type of experiment in which except for only one variable, everything is kept constant.

The common type of the controlled experiment compares the control group against the experimental group. All the variables are identical between two groups except factor which is being tested.

Big advantage of the controlled experiment is that one can eliminate much of uncertainty about the results.

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3 years ago
What is 3/18 in simplest form
Novosadov [1.4K]

Answer:

1/6

Step-by-step explanation:

3/18 divided by 3

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3 years ago
Read 2 more answers
When temperature is zero degree Celsius, the Fahrenheit temperature is 32. When the Celsius temperature is 100, the correspondin
7nadin3 [17]

Answer:

\\ y = 1.8(x) + 32 or \\ y = \frac{9}{5}(x) + 32

or equivalently:

\\ F = 1.8(C) + 32 or \\ F = \frac{9}{5}(C) + 32

Step-by-step explanation:

To express the Fahrenheit temperature <em>as a linear function of the Celsius temperature</em>, F(c), we can proceed as follows.

We can use here <em>the two-point form</em> <em>equation</em> of a line:

\\ y-y_1 = \frac{y_2 - y_1}{x_2 - x_1}(x-x_1) [1]

We are asked to express the <em>Fahrenheit temperature</em> as a function of <em>Celsius temperature</em>, so the independent variable, in this case, is <em>x</em> (Celsius temperature) and the dependent variable is <em>y</em> (Fahrenheit temperature).

When temperature is zero degree Celsius (\\x_1 = 0), the Fahrenheit temperature is 32 (\\y_1 = 32).

When the Celsius temperature is 100 (\\x_2 = 100), the corresponding Fahrenheit temperature is 212 (\\y_2 = 212).

Then, using [1], we have:

\\ y-32 = \frac{212 - 32}{100 - 0}(x-0)

\\ y-32 = \frac{180}{100}(x)

\\ y-32 = 1.8(x).

It could be also be written as:

\\ y-32 = \frac{18}{10}(x) = \\ y-32 = \frac{9}{5}(x), as it commonly appears in books.

Then <em>the Fahrenheit temperature express as a linear function of the Celsius temperature, F(c</em>) is ( solving the equation for <em>y </em>) :

\\ y = 1.8(x) + 32 or \\ y = \frac{9}{5}(x) + 32.

Or equivalently:

\\ F = 1.8(C) + 32 or \\ F = \frac{9}{5}(C) + 32

We can check this using the given values from the question:

For 0 Celsius degrees, the Fahrenheit temperature is:

\\ y = 1.8(0) + 32 = 32 Fahrenheit degrees.

For 100 Celsius degrees, the Fahrenheit temperature is:

\\ y = 1.8(100) + 32 = 180 + 32 = 212 Fahrenheit degrees.

5 0
3 years ago
Plzzzzzzzzzzzzzzzzzzzz
Salsk061 [2.6K]

Answer:

B

Step-by-step explanation:

I graphed the equation, and the highest point was at 3.7 feet in the air, 4 seconds into the flight. See the graph below. Hope this helps!

8 0
3 years ago
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