This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.
Area of a rectangle:
The area of rectangle of length l and width w is given by:
w(2w + 3) = 9
From this, we get that:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots 
such that 
, given by the following formulas:
In this question:
Thus a quadratic equation with 
Then
Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.
Another similar problem can be found at brainly.com/question/16995958
The distance travelled by an object is 50 m.
<h3>What is Distance?</h3>
The distance between two points is the length of the path connecting them.
Here, given equation of distance
S = 1/2 (u + v)t
Where s is the distance traveled by an object (in meters)
initial velocity u (in m/s)
final velocity v (in m/s).
t in seconds.
Now, given values are;
u = 8 m/s ; v = 12 m/s ; t = 5 sec.
S = 1/2 (8 + 12)5
S = 1/2 (20)5
S = 100/2
S = 50 m.
Thus, the distance travelled by an object is 50 m.
Learn more about Distance from:
brainly.com/question/15172156
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Answer:
Step-by-step explanation:
r = Radius of semicircle = 
Area of semicircle is given by
The area of the semicircle is 
.
