Since the problem is 2x^2-5xy-y^3 we first have to plug in what the x and y stands for, once you do that your problem should look like this:
2(-3)^2- 5(-3)(-2)- (-2)^3
Now take the parentheses away and when you do that your signs change.
2x3^2-5x(-3)x(-2)-(-2)^3
do it again with -5x(-3)x(-2)
2x3^2-30-(-2)^3
now do this with (-2)^3
2x3^2-30-(-8)
Now evaluate the power
3^2 becomes 9
2x9-30-(-8)
then change -(-8) to a positive since two negatives make a positive
2x9-30+8
Now multiply the numbers 2x9
18-30+8
Then do 18-30 which equals -12 then add 8
Now you are left with your answer:
<u>-4</u>
Hope this helps! :3
Answer:
5
Step-by-step explanation:
8x - 6 > 12 + 2x
Subtract 2x from each
8x -2x -6 > 12+2x-2x
6x -6 > 12
Add 6 to each side
6x -6+6 > 12+6
6x > 18
Divide by 6
6x/6 > 18/6
x > 3
The only value greater than 3 is 5
Answer:
x = 2.36603 or 0.633975
Step-by-step explanation:
Here we want to solve the quadratic equation using the completing the square method.
2x^2-6x + 3 = 0
divide through by 2 first;
x^2 -3x + 3/2 = 0
x*2 -3x = -3/2
Half the x term will be -3/2 and squaring it is 9/4
we add this to both sides
x^2-3x/2 + 9/4 = -3/2 + 9/4
(x-3/2)^2 = 3/4
Finding square root of both sides
x-3/2 = √(3/4)
x = 3/2 ± √(3/4)
x = 3/2 + √(3/4) or x = 3/2-√(3/4)
which becomes
x = 2.36603 or 0.633975
0.71358024691
If you are rounding then the answer would be 0.71
Answer: they are both the same fraction
