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Masja [62]
3 years ago
5

Evaluate the expression n=2. 8(n + 1) = ___

Mathematics
2 answers:
kykrilka [37]3 years ago
8 0

Answer:

I believe it's 24

Step-by-step explanation:

because 2+1 is 3 and then 3 times 8 is 24

Nimfa-mama [501]3 years ago
4 0

Answer:

24

Step-by-step explanation:

Equation: 8(n + 1)

Plug in n = 2

New equation: 8(2 + 1)

Simplify: 8(3)

Simplify: 24

<u>Answer: 24</u>

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Ne4ueva [31]
I am pretty sure that the answer is 3
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4 years ago
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What is the distance between -7 and 3?<br> A. 4<br> B. -4<br> C. 9<br> D. 10
givi [52]
The answer is 10 generally
8 0
3 years ago
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Find equations of the following.3(x − z) = 12arctan(yz), (1 + π, 1, 1)(a) the tangent plane (b) parametric equations of the norm
dexar [7]

Answer:

A.-x+2y+z=2-\pi

B.x=\frac{-t}{\sqrt{6}}+1+\pi, \ y=\frac{2t}{\sqrt{6}}+1, \ z=\frac{t}{\sqrt{6}}+1

Step-by-step explanation:

A. At first, it´s useful to move everything to one side and name it as a function f(x,y,z):

f(x,y,z)= 12arctan(yz)-3x+3z:

To proceed to find the tangent plane at (1+π,1,1), we use the following equation for the tangent plane:

\nabla{f(x_{0},y_{0},z_{0})*(x-x_{0},y_{0},z-z_{0})=0

Where (x₀,y₀,z₀) is the specified point where we want the tangent plane to connect. Now we need to find the gradient vector of f:

\nabla{f(x,y,z)}=(\frac{\delta{f}}{\delta{x}},\frac{\delta{f}}{\delta{y}},\frac{\delta{f}}{\delta{x}})

Now we differentiate f with respect to x,y and z to find those coordinates:

\nabla{f(x,y,z)}=(-3,\frac{12z}{1+(yz)^{2}},3)

\nabla{f(1+\pi,1,1)}=(-3,\frac{12}{2},3)=(-3,6,3)\\

We are ready to use the equation for the tangent plane

(-3,6,3)*(x-1-\pi,y-1,z-1) = 0\\3+3\pi-3x+6y-6+3z-3=0\\-3x+6y+3z=6-3\pi\\-x+2y+z=2-\pi

The tangent plane has an equation -x+2y+z=2-\pi, and the orthogonal vector to this plane is one made of the coefficients of the plane, a normal vector for this plane is (-1,2,1).

To find a normal line to this surface in (1+π,1,1) we find a normal line to the plane, and because we know that (-1,2,1) is a normal vector, then the line has to have the same direction, so we normalize that vector to get the direction:

\|v\|=\sqrt{(-1)^{2}+2^{2}+1^{2}}=\sqrt{6}\\v_{1}=(\frac{-1}{\sqrt{6}},\frac{2}{\sqrt{6}},\frac{1}{\sqrt{6}})

And because that line has to pass through (1+π,1,1) we conclude the vector equation for this line is the following:

\overrightarrow{V}(t)=(\frac{-1}{\sqrt{6}},\frac{2}{\sqrt{6}},\frac{1}{\sqrt{6}})t+(1+\pi,1,1)

and from this equation:

x=\frac{-t}{\sqrt{6}}+1+\pi\\y=\frac{2t}{\sqrt{6}}+1\\z=\frac{t}{\sqrt{6}}+1

6 0
3 years ago
2×-4y=24<br> -6+4y=-24<br> What the answer??????
jek_recluse [69]
{ 2x - 4y = 24
{ - 6x + 4y = - 24    ⇒ ( - 4y + 4y = 0 )

2x - 6x = 24 - 24
- 4x = 0  .(-1)
  4x = - 0
    x = <u>- 0</u> 
           4
    x = 0

2x - 4y = 24
2.0 - 4y = 24
0 - 4y = 24
- 4y = 24 .(-1)
  4y = - 24
   y = <u>- 24</u>
           4
   y = - 6

S = { 0,-6}
<u>
</u>
8 0
4 years ago
Find the value of x<br><br> x = __
asambeis [7]

Answer:

x=9

Step-by-step explanation:

By the Isosceles Triangle Theorem the angles opposite to the congruent angles in an isosceles triangle are congruent.

So 2x-10=8

x=9

4 0
3 years ago
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