Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Answer:
Copy the second line segment with one endpoint at the same endpoint of the first line segment.
c is correct a is wrong
Answer:
The tip would be worth $2.19
Step-by-step explanation:
x - is the full bill
1/20 x = $0.73
Solve for x:
Multiply both sides by 20.
<u>20</u>*(1/20 x) = <u>20</u>*(0.73)
x = 14.6
Now we just have to find 15% of x to find the tip.
3/20 (14.6) = 2.19
So, the tip would be worth $2.19
Answer:
1.6 + 1.6 + 1.6 + 3.1 = 7.9 miles walked
Answer:
Step-by-step explanation:
By 2 for the first one. And for 2 they skip counting by 6
