ALTITUDE
the altitude is the height of the traignel
if we graph the points, we get some lopsided triangle
so we know the altitude is peerpendicular to the base
so find the line that is perpendicular to the line tha passes through A and C
so first fid the line that passes through (-4,-2) and (18,-8)
slope=(y2-y1)/(x2-x1)
slope=(-8-(-2))/(18-(-4))=(-8+2)/(18+4)=-6/22
perpendicular lines have slopes the multipy to -1
-6/22 times what=-1
times both sides by -22/6
wat=22/6
that is the slope of the line that is the altitude
we have to use point slope form
the equation of a line that passes through (x1,y1) and has sloe of m is
y-y1=m(x-x1)
so passes through B (4,4) and has slope of 22/6
y-4=22/6(x-4)
y-4=22/6x-44/3
y=(22/6)x-32/3
that is the altitude
MEDIAN
the media is the line joining the midpoint of one side to the vertex of the other
so we need to find the line that passes through the midpoint of AB and through the point C
midpoint of (x1,y1) and (x2,y2) is
((x1+x2)/2,(y1+y2)/2)
so
midopint of (-4,-2) and (4,4) is
((-4+4)/2,(-2+4)/2)=(0/2,2/2)=(0,1)
so we just find the line that passes through (0,1) and (18,-8)
slope iis (-8-1)/(18-0)=-9/18=-1/2
a point is (0,1) and sloe si -1/2
y-1=-1/2(x-0)
y-1=1/2x
y=(1/2)x+1
ALTITUDE
y=(-6/22)x
MEDIAN:
y=(1/2)x+1
Answer:
Axis of symmetry runs along -1
Step-by-step explanation:
<u>formula used</u>
-b/2a
<u>Plug variables in</u>
-2/2
-1
Answer:
c
Step-by-step explanation:
Answer:
Let's cut the figure into:
Parallelogram, square, and rectangle.
Let's find the area of the parallelogram first:
10 x 3.5 = 35
Let's find the area of the square:
4 x 4 = 16
When given one length of a square you already know are sides and lengths are equal so therefore 1 given length of a square is all the lengths.
Let's find the area of a rectangle:
6 x 12.5 = 75
Now let's add all the areas up:
35 + 16 + 75 = 126 square inches is your answer.