If x = 1, then 3*1 = 3 which when modded with 5, we get 3 as a remainder. In other words, 3/5 = 0 remainder 3. We don't use the quotient at all when it comes to modular arithmetic. All we care about is the remainder.
If x = 2, then 3*2 = 6 which leads to remainder 1 when we divide by 5. Therefore, 3x = 1 (mod 5) when x = 2.
If x = 3, then 3*3 = 9 = 4 (mod 5) because 9/5 = 1 remainder 4.
So 3x = 4 (mod 5) when x = 3.
<h3>The final answer is C) 3</h3>
We don't need to check D since x = 3 is a solution and it's smaller than x = 4.
If you wanted to check x = 4, then 3*4 = 12 = 2 (mod 5) because 12/5 yields a remainder of 2.
Answer:
She got an equally good deal both times
Step-by-step explanation:
can be simplified to make 
can be simplified to make 
they are the same
Answer:
a = 
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.:
<em>Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean theorem and then find the values of the six trigonometric functions for angle B. when b=3 and c=4</em>.
My answer:
We will Pythagoras theorem, which states that the sum of squares of two legs of a right triangle is equal to the square of the hypotenuse of right triangle. Because the question says that ABC is a right triangle.

Given that: b=3 and c=4

so a =
We know that tangent relates opposite side of a right triangle with adjacent side.

Please have a look at the attached photos.
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation;
3*n-4-(14)=0
Pull out like factors :
3n - 18 = 3 • (n - 6)
Solve : 3 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solve : n-6 = 0
Add 6 to both sides of the equation :
n = 6
We are told that the children from a football club are put into rows in the sports hall. When put into rows of 9 children there are 2 children left over. When put into rows of 12 children there are 2 children left over.
We will find least number of children in football club by finding LCM of 9 and 12.
Multiples of 9 are: 9, 18, 27, 36, 45, 54, 63,...
Multiples of 12 are: 12, 24, 36, 48, 60, 72, 84,...
We can see that least common multiple of 9 and 12 is 36.
We are told that 2 children left over from putting them into 9 and 12 children per row. To find least number we will add 2 to 36.


Therefore, the least number of children in the football club is 38.