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ad-work [718]
3 years ago
15

60 = −2(−10 − 4x) what is the answer show step by step

Mathematics
2 answers:
Papessa [141]3 years ago
8 0
That’s the answer with steps

Pavel [41]3 years ago
5 0

Answer: x = 5

Step-by-step explanation:

first, divide both sides.

30 = -(-10 - 4x)

then, remove the parenthesis.

30 = 10 + 4x

them, move the terms.

=4x = 10 - 30

finally, divide both sides.

-4x = 20

solution: x = 5

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Need some help please
Pie

Answer:

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3 years ago
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How to make a graph of an exponential function that shows exponential decay and has a y intercept of 2
Sliva [168]

Answer:

f(x)=2e^{-kx}

in a graph the x value at the y intercept is 0

f(x)=Ae^{-kx}  is a typical decay function

if x = 0  thus e^{-kx} = 1

so at 0 the function value would be A

f(x)=2e^{-kx}

Step-by-step explanation:

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3 years ago
May someone please explain to me how to do this in the easiest way? I don't really understand. Thanks❤
katrin [286]
Ok, so 1 is a whole number.  1/5 is a fraction of 1.  So you want to subtract 1/5 from 1.  The number 1 is equal to 5/5.  So if you subtract 1/5 from 5/5 you are left with 4/5.  You do the same with the second one, just subtract 3/5 from 5/5 to get your answer.
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3 years ago
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Which of these are like terms in the following expression:
kumpel [21]

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The second one (3x, 9x)

Step-by-step explanation:

Like terms are the terms that either have the same variable or have no variable.

7 0
3 years ago
The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the
sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}

When we use this to replace the 't" in the displacement formula, we et:

y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

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3 years ago
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