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kondaur [170]
3 years ago
6

Take a factor out of the square root √(48x^2) , where x≤0

Mathematics
1 answer:
harkovskaia [24]3 years ago
4 0

The expression \sqrt{48x^2} can be simplified,

\sqrt{48x^2}=\sqrt{48}\sqrt{x^2}=x\sqrt{3\cdot4^2}=4x\sqrt{3}.

Hope this helps.

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Read 2 more answers
Can someone help me solve these two problems? i need to find what x is.
Bond [772]

Answer:

1. x=2

2. x= 0.33

Step-by-step explanation:

1.So to start off you have a coefficient for 2 so you have to find what 2 to the power of 2 is =4 so then you have your new problem 4x+5=13 next you need to get 4x by itself so

-5 -5

then you have 4x=8. you divide by 4 on both sides

4. 4

so then you get x=2

2.So same here find what 3 to the power of 2 is =9

New equation 4x-1=9x+4x-4. Then combine like terms on the right you cant do it on the left because that is a separate part and those dont merge like terms so

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new equation. 4x-1=13x-4

next subtract 4x on both sides

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next add 4 to both sides

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new equation. 3=9x

so then divide 9 on both sides

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x= 0.33

Hope this made sense and helps

7 0
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