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Veseljchak [2.6K]
3 years ago
5

Can someone help me plzzz ASAP.

Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0

Ansgreek myth

Step-by-step explanation:

coool beans

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Divide and write in simplest form 8/9 divided by 12
likoan [24]

8/9 divided by 12 is 2/27

its simplest form would be 2/27

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4 years ago
Solve
tino4ka555 [31]

Answer:

(a) h = A/2πr

(b) 360.375

Step-by-step explanation:

(a) divide both sides by 2πr

h = A/2πr

(b) h= 93 / 2*3.1*2.5

= 360.375

8 0
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Scott's gas tank is 1/4 full. After he buys 10 gallons of gas, it is 2/3 full. How many gallons can Scott's tank hold?
Virty [35]

Scott's gas tank is a 1/4 full.

After he buys 10 gallons of gas, it is 2/3's full.

The difference between 1/4 and 2/3 is 5/12.

Which means 5/12th is 10 gallons of gas.

Full tank will hold 10 x 12/5 gallons of gas.

So, Scott's tank can hold 24 gallons of gas.

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3 0
3 years ago
Arrange in order from least to greatest: 0.5, 1/4, 0.4?<br><br>​
PSYCHO15rus [73]

Answer:

first 1/4, second 0.4, third 0.5

7 0
3 years ago
Read 2 more answers
A guitar string is plucked at a distance of 0.6 centimeters above its resting position and then released, causing vibration. The
liubo4ka [24]

Answer:

The equation that represents the motion of the string is given by:

y =Ae^{-kt}\cos(2\pi ft)     .....[1] where t represents the time in second.

Given that: A = 0.6 cm (distance above its resting position) , k = 1.8(damping constant) and frequency(f) = 105 cycles per second.

Substitute the given values in [1] we get;

y =0.6e^{-1.8t}\cos(2\pi 105t)  

or

y =0.6e^{-1.8t}\cos(210\pi t)  

(a)

The trigonometric function that models the motion of the string is given by:

y =0.6e^{-1.8t}\cos(210\pi t)

(b)

Determine the amount of time t that it takes the string to be damped so that -0.24\leq y \leq0.24

Using graphing calculator for the equation

y =0.6e^{-1.8x}\cos(210\pi x)

let x = t (time in sec)  

Graph as shown below in the attachment:

we get:

the amount of time t that it takes the string to be damped so that -0.24\leq y \leq0.24 is, 0.5 sec


4 0
3 years ago
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