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3 years ago

What is the height of a trapezoid with a area of 79.2 and bases 4.2 and 9

Mathematics

2 answers:

julsineya [31]3 years ago

8 0

The answer to this problem is 12. If you want me to write it out I can

ycow [4]3 years ago

8 0

A=area
b₁=base 1
b₂=base 2
h=heigth

A=(1/2)h(b₁+b₂)
79.2=(1/2)h(4.2+9)
79.2=(1/2) h (13.2)
h=(79.2 * 2) / (13.2)=158.4 / 13.2=12

Answer: height=12

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3 years ago

Solving for matrices

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Answer:

Step-by-step explanation:

The augmented matrix for the system of three equaitons is

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$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&6&-6&|&18\end{array}\right)$

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$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&1&-1&|&3\end{array}\right)$

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You get the system of three equations:

$\left\{\begin{array}{r}3x-4y-5z=-27\\-26y-19z=-168\\-45z=-90\end{array}\right.$

From the third equation

$z=\dfrac{90}{45}=2.$

Substitute z=2 into the second equation:

$-26y-19\cdot 2=-168\\ \\-26y-38=-168\\ \\-26y=-168+38=-130\\ \\y=\dfrac{130}{26}=5.$

Now substitute z=2 and y=5 into the first equation:

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3 years ago

Complete the equation of the line through ( 4 , -8 ) and ( 8 , 5 )

irinina [24]

Answer:

Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is

13x - 4y = 84.

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( 4 ,-8)

point B( x₂ , y₂) ≡ (8 , 5)

To Find:

Equation of Line AB =?

Solution:

Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

$(y - y_{1} )=(\frac{y_{2}-y_{1} }{x_{2}-x_{1} })\times(x-x_{1}) \\$

Substituting the given values in a above equation we get

$(y-(-8))=(\frac{5-(8)}{8-4})\times (x-4)\\ \\(y+8)=\frac{13}{4}(x-4)\\\\4(y+8)=13(x-4)\\4y+32=13x-52\\13x-4y=84...............\textrm{which is the required equation of the line AB}$

Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is

13x - 4y = 84.

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3 years ago