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garri49 [273]
3 years ago
8

What is the height of a trapezoid with a area of 79.2 and bases 4.2 and 9

Mathematics
2 answers:
julsineya [31]3 years ago
8 0
The answer to this problem is 12. If you want me to write it out I can
ycow [4]3 years ago
8 0
A=area
b₁=base 1
b₂=base 2
h=heigth

A=(1/2)h(b₁+b₂)
79.2=(1/2)h(4.2+9)
79.2=(1/2) h (13.2)
h=(79.2 * 2) / (13.2)=158.4 / 13.2=12

Answer: height=12
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1 A can in the shape of a cylinder has a diameter of 6 centimeters and a height of 10
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radius r = 3 cm

height h = 10 cm

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top surface area T = 28.2743339 cm^2

base surface area B = 28.2743339 cm^2

total surface area A = 245.044227 cm^2

In Terms of Pi π

volume V = 90 π cm3

lateral surface area L = 60 π cm^2

top surface area T = 9 π cm^2

base surface area B = 9 π cm^2

total surface area A = 78 π cm^2

Step-by-step explanation:

Cylinder Formulas in terms of r and h:

Calculate volume of a cylinder:

V = πr2h

Calculate the lateral surface area of a cylinder (just the curved outside)**:

L = 2πrh

Calculate the top and bottom surface area of a cylinder (2 circles):

T = B = πr2

Total surface area of a closed cylinder is:

A = L + T + B = 2πrh + 2(πr2) = 2πr(h+r)

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h = height

V = volume

L = lateral surface area

T = top surface area

B = base surface area

A = total surface area

π = pi = 3.1415926535898

√ = square root

8 0
3 years ago
Read 2 more answers
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