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3 years ago

What is the height of a trapezoid with a area of 79.2 and bases 4.2 and 9

Mathematics

2 answers:

julsineya [31]3 years ago

8 0

The answer to this problem is 12. If you want me to write it out I can

ycow [4]3 years ago

8 0

A=area
b₁=base 1
b₂=base 2
h=heigth

A=(1/2)h(b₁+b₂)
79.2=(1/2)h(4.2+9)
79.2=(1/2) h (13.2)
h=(79.2 * 2) / (13.2)=158.4 / 13.2=12

Answer: height=12

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Step-by-step explanation:

Let n be the unknown number.

The reciprocal basically makes the number (n in this case) a fraction. So, that being said, the reciprocal of n would be $\frac{1}{n}$ .

The difference of three and the reciprocal of a number ( $\frac{1}{n}$ ) would be $\frac{1}{n}$ - 3.

The quotient of 20 and the number (n) would be $\frac{20}{n}$ .

So, with this information we've gathered so far, we can come up with an equation to find what the number equals.

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