1/10=x hope that helps a bunch
NO it is not possible when dividing an irregular shape to polygons to overlap. Every polygon would be broken up in piece.
Answer:
1.89
Solution:
We have -44x - 86 = -3
First, we move the non x terms to the RHS of the equation. To do this, we add 86 to both sides.
Note: if a = b, then a + c = b + c
Therefore, -44x - 86 + 86 = -3 + 86
or, -44x = 83
Next, divide both sides by -44, which is the coefficent of x
Note: if a = b, then a ÷ c = b ÷ c
-44x
-44
=
83
-44
or, x = -1.89
Explaination:
This is right I guess
m∠AOC = m∠AOB + m∠BOC
We have m∠AOC = 19°, m∠AOB = 4x - 15 and m∠BOC = 2x + 10. Substitute:
19 = (4x - 15) + (2x + 10)
19 = (4x + 2x) + (-15 + 10)
19 = 6x - 5 <em>add 5 to both sides</em>
24 = 6x <em>divide both sides by 6</em>
4 = x
m∠BOC = 2x + 10 → m∠BOC = 2(4) + 10 = 8 + 10 = 18
m∠AOB = 4x - 15 → m∠AOB = 4(4) - 15 = 16 - 15 = 1
<h3>Answer: c. m∠BOC = 18°, m∠AOB = 1°</h3>