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Pachacha [2.7K]
3 years ago
6

The product of a number and -3, increased by 8 is 20. I need help. >:

Mathematics
2 answers:
pychu [463]3 years ago
8 0

Answer:

-4

Step-by-step explanation:

-3(x)+8=20

-3x=12

x=-4

Black_prince [1.1K]3 years ago
4 0
Answer.) -4

Hope this helped!
You might be interested in
Which expression is equivalent to<br> (fg) (5)? <br> F(5)* g(5) <br> F(5)+g(5)<br> 5f(5)<br> 5g(5)
Alexxandr [17]

Answer:

they F (5) g (5)

Step-by-step explanation:

(fg)=(f.g)

and then this is the first doing (fg)(X)= f(x) [g(x)]

x=5

f(5).g(X)

and they final result is

they top of answer

happy answering

5 0
3 years ago
F(x) = x2. What is g(x)?
ludmilkaskok [199]

Answer:

g(x)=3x(superscript)2

8 0
3 years ago
Read 2 more answers
Help needed asap!!!!!!!​
Alexxandr [17]

Answer:

8.2

Step-by-step explanation:

w-x+z

-2.1-(-7)+3.3

-2.1+7+3.3

8.2

Hope this helps!

6 0
3 years ago
1)
Anika [276]

Answer:a,c,d

Step-by-step explanation:

8 0
3 years ago
Use the definition of the derivative to differentiate v=4/2 pie r^3
nata0808 [166]

I suspect 4/2 should actually be 4/3, since 4/2 = 2, while 4/3 would make V the volume of a sphere with radius r. But I'll stick with what's given:

\displaystyle \frac{dV}{dr} = \lim_{h\to0} \frac{2\pi(r+h)^3-2\pi r^3}{h}

\displaystyle \frac{dV}{dr} = 2\pi \lim_{h\to0} \frac{(r^3+3r^2h+3rh^2+h^3)- r^3}{h}

\displaystyle \frac{dV}{dr} = 2\pi \lim_{h\to0} \frac{3r^2h+3rh^2+h^3}{h}

\displaystyle \frac{dV}{dr} = 2\pi \lim_{h\to0} (3r^2+3rh+h^2)

\displaystyle \frac{dV}{dr} = 2\pi \cdot 3r^2 = \boxed{6\pi r^2}

In Mathematica, you can check this result via

D[4/2*Pi*r^3, r]

3 0
3 years ago
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