Answer:
that is a lot
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
The domain does not exist when the denominater of an equation is zero. So in this case if x was -2 and we added 2 the denominator would be zero, and that value does not exist in the domain. Hope this helps!
For f(x), which has a vertex at (2,0), the y-intercept at (0,4) is above this vertex, so the parabola opens upward. This means that the vertex is the only point that touches the x-axis, so there is only 1 x-intercept.
For h(x), the graph does not have any x-intercepts.
For g(x) = x^2 + x - 2 = (x+2)(x-1), this intersects the x-axis at x = -2 and x = 1, so there are 2 x-intercepts.
From least to greatest: h(x), f(x), g(x).
Answer:
x(x²+3)
x³+3x
Step-by-step explanation:
Hope it helps you
Answer:
c because i did it
Step-by-step explanation:
