Let z = sin(x).
.. z^2 -2z = 2
.. z^2 -2z +1 = 3
.. (z -1)² = 3
.. z -1 = ±√3
.. z = 1 -√3 . . . . . the positive solution is extraneous
sin(x) = 1 -√3
The answer is x=7 hope this helps:)
Answer:
x = ± 2i
Step-by-step explanation:
The equation has no real roots, gut has complex roots
Given
x² = - 4 ( take the square root of both sides )
x = ± 
= ± 
[ Note that
= i ]
= ±
×
= ± 2i