Find the perimeter of the triangle with vertices (−2,2), (0,4), and (1,−2). the perimeter is . round to the nearest hundredth.

1 answer:

4 0

The answer is about 12.5 (when rounded to the nearest 10th).

This can be found using the distance formula between each point. One distance is 5, one is $\sqrt{2}$ and one is $\sqrt{37}$ . Added together gives you the answer above.

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Korolek [52]

The solution to the problem is as follows:
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the genaral term is 5Cr(-1)^r 2^r x^(5-2r)
and so need 5-2r = -1 => r = 3
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