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solmaris [256]
3 years ago
13

If θ is a first-quadrant angle in standard position with P(u, v) = (3, 4), evaluate sin 2 θ

Mathematics
2 answers:
kenny6666 [7]3 years ago
4 0

Answer:

24/25

Step-by-step explanation:

sin 2 θ = 3÷25/8 =24/25

from web2calc

VikaD [51]3 years ago
4 0

Answer:

24/25

Step-by-step explanation:

P(u, v) = (3, 4) describes a triangle:  One vertex is at the origin (0, 0) and the other at (3, 4).  According to the Pythagorean Theorem, 3^2 + 4^2 = 5^2, so we know the hypotenuse length is 5 units.

Recall that the sine function is defined as opp/hyp, which here is 4/5, and that the cosine function as adj/hyp, which here is 3/5.  

Finally, we'll apply the double angle formula sin 2x = 2 sinx cos x.

Substituting the values found above,              sin 2x = 2(4/5)(3/5) = 24/25.

The sine of 2x (where x is the smaller acute angle whose vertex is (0, 0) ) is 24/25.

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Varvara68 [4.7K]

Answer:

1728

Step-by-step explanation: L(length) H(height) W(width)

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2 years ago
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Pachacha [2.7K]

4b^2 x 2b^4 - step 1

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4 years ago
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yuradex [85]
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3 years ago
-(m-3)=5m-(6m-7)-4 solve?
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Answer:

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-m-5m+6m = 7-4-3

0m= 0

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