The work shows how to use long division to find (x2 + 3x –9) ÷ (x – 2).

Mathematics

2 answers:

sasho [114]3 years ago

8 0

Answer:

1/x-2

Step-by-step explanation:

welcome ;P

skelet666 [1.2K]3 years ago

5 0

Hey!

The first step to solving the rest of this problem would be to distribute the parenthesis in -( 5x - 10 ).

Original Equation :
-( 5x - 10 )

New Equation {Changed by Distributing the Parenthesis} :
- ( 5x ) - ( -10 )

Now we'll simplify the equation.

Old Equation :
- ( 5x ) - ( -10 )

New Equation {Simplified} :
-5x + 10

Okay, now that that part of the equation has been changed, we can add the simplified part to our entire equation.

New Equation :
5x - 9 - 5x + 10

Next we need to group like terms.

Old Equation :
5x - 9 - 5x + 10

New Equation {Changed by Grouping Like Terms} :
5x - 5x - 9 + 10

And now we add the similar elements.

Old Equation :
5x - 5x - 9 + 10

New Equation {Changed by Grouping Like Terms} :
-9 + 10

And finally we simply add the numbers.

Old Equation :
-9 + 10

Solution {Old Equation Solved} :
1

So, this means that 5x - 9 - ( 5x - 10 ) is 1.

Hope this helps!

- Lindsey Frazier ♥

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natulia [17]

Answer:

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3 years ago

Alexander Litvinenko was poisoned with 10 micrograms of the radioactive substance Polonium-210. Since radioactive decay follows

koban [17]

Answer:

The amount of Polonium-210 left in his body after 72 days is 6.937 μg.

Step-by-step explanation:

The decay rate of Polonium-210 is the following:

$N(t) = N_{0}e^{-\lambda t}$ (1)

Where:

N(t) is the quantity of Po-210 at time t =?

N₀ is the initial quantity of Po-210 = 10 μg

λ is the decay constant

t is the time = 72 d

The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.

First, we need to find the decay constant:

$\lambda = \frac{ln(2)}{t_{1/2}}$ (2)

Where t(1/2) is the half-life of Po-210 = 138.376 days

By entering equation (2) into (1) we have:

$N(t) = N_{0}e^{-\frac{ln(2)}{t_{1/2}}*t}} = 10* \frac{99.498}{100}*e^{-\frac{ln(2)}{138.376}*72} = 6.937 \mu g$

Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.

I hope it helps you!

8 0

3 years ago

Factor the expression -45x^2 +5

klemol [59]

$-45x^2 +5 \\ \\ GCF = 5 \\ \\ 5( \frac{45x^2}{5} - \frac{5}{5} ) \\ \\ -5(9x^2-1) \\ \\ -5((3x)^2-1^2) \\ \\ -5(3x+1)(3x-1) \\ \\ Answer: \fbox {-5(3x+1)(3x-1)}$