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Mrrafil [7]
3 years ago
14

The work shows how to use long division to find (x2 + 3x –9) ÷ (x – 2).

Mathematics
2 answers:
sasho [114]3 years ago
8 0

Answer:

1/x-2

Step-by-step explanation:

welcome ;P

skelet666 [1.2K]3 years ago
5 0
Hey!


The first step to solving the rest of this problem would be to distribute the parenthesis in -( 5x - 10 ).

<em>Original Equation :</em>
-( 5x - 10 )

<em>New Equation {Changed by Distributing the Parenthesis} :</em>
- ( 5x ) - ( -10 )

Now we'll simplify the equation.

<em>Old Equation :</em>
- ( 5x ) - ( -10 )

<em>New Equation {Simplified} :</em>
-5x + 10

Okay, now that that part of the equation has been changed, we can add the simplified part to our entire equation.

<em>New Equation :</em>
5x - 9 - 5x + 10

Next we need to group like terms.

<em>Old Equation :</em>
5x - 9 - 5x + 10

<em>New Equation {Changed by Grouping Like Terms} :</em>
5x - 5x - 9 + 10

And now we add the similar elements.

<em>Old Equation :</em>
5x - 5x - 9 + 10

<em>New Equation {Changed by Grouping Like Terms} :</em>
-9 + 10

And finally we simply add the numbers.

<em>Old Equation :</em>
-9 + 10

<em>Solution {Old Equation Solved} :</em>
1

<em>So, this means that 5x - 9 - ( 5x - 10 ) is</em>  1.

Hope this helps!


- Lindsey Frazier ♥
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The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individual
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\Huge\bf{\underline{\red \dag { Aиѕωєя }}} \red \dag

4 Packs of water and 7 Packs of candy bars.

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Find the Least Common Multiple (LCM), but to find the LCM we need to find the prime factorization of each of the following number :-

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\sf \green{ \frac{140}{20}  = 7 \: packs \: of \: candy \: bars}

<u>___________________</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

6 0
3 years ago
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