The acceleration due to gravity is 3 m/s^2 and the work done is -4.3 J.
<h3>What is the acceleration due to gravity?</h3>
Now we must use the formula;
h = ut + 1/2gt^2
Since it was dropped from a height u = 0 m/s
h = height
u = initial velocity
g = acceleration due to gravity
t = time
h = 1/2gt^2
g = 2h/t^2
g = 2 * 2.85 /(1.38)^2
g = 5.7/1.9
g = 3 m/s^2
The work that must be done is against gravity hence;
W = -(mgh)
W = - (0.5 kg * 3 m/s^2 * 2.85 m)
W = - 4.3 J
Learn more about acceleration due to gravity:brainly.com/question/13860566
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Explanation:
Answer: we divide this equation by pV and use {C}_{p}={C}_{V}+ . ... The temperature, pressure, and volume of the resulting gas-air mixture
Explanation:
Answer:
C: time of contact is increased
Explanation:
When a ball is falling from height, it maintains the same mass but velocity may change depending on the conditions in that environment.
Now, to catch the ball on your palm, you need to find a way to reduce the momentum of the ball upon hitting your hand.
Now, to reduce the momentum, we need to apply impulse.
This is because we know that;
Impulse(I) = F × t = change in momentum (m(v - u))
Thus;
I = Ft
F = I/t
We are told that extending the hand reduces the force of contact on your hand.
Thus;
For F which is the force to be reduced, the denominator (t) has to be increased.
Thus, the correct answer is that time of contact is increased