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crimeas [40]
3 years ago
11

Suppose you have two magnets. Magnet A doesn't have its poles labeled, but Magnet B does have a clearly labeled north and south

pole. If these two are brought into contact with one another, which of the following could you expect?
A. The side of Magnet A that's attracted to Magnet B's north pole must be Magnet A's north pole.
B. The side of Magnet A that's repelled by Magnet B's south pole must be Magnet A's north pole.
C. The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole.
D. The side of Magnet A that's repelled by Magnet B's north pole must be Magnet A's south pole
Physics
2 answers:
Svetllana [295]3 years ago
8 0

Like poles of 2 magnets Repel each other and unlike poles attract each other. so the answer would be C. the side of magnet A that's attracted to Magnet B's South pole must be Magnet A's North pole.

Levart [38]3 years ago
4 0
<span>The right answer here would be option C - the side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole. This is due to the magnetic rule of opposites attracting.</span>
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prohojiy [21]

Answer:

A) The process that give us day  and night.

Explanation:

From the answer choices provided the one that is not an example of this is the process that give us day  and night. This is because, the day/night cycle occurs as the Earth spins on it's axis. This cause one side of the Earth to be facing the Sun, which is the side that is currently experiencing day time while the other side is experiencing night time. As the Earth spins the cycles repeat. This is not an example of revolving.

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3 years ago
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DiKsa [7]

Answer:

V = 0.0723 volts = 72.3 milivolts

Explanation:

The emf induced in the rod is the motional emf due to the magnetic field. This motional emf can be calculated by the following formula:

EMF = V = vBl Sin\theta

where,

V = Motional EMF = ?

v = speed of rod = 12.5 m/s

B = Magnetic Field = 6.23 mT = 0.00623 T

l = Length of rod = 92.9 cm = 0.929 m

θ = angle between v and B = 90°

Therefore,

V = (12.5\ m/s)(0.00623\ T)(0.929\ m)Sin\ 90^o\\

<u>V = 0.0723 volts = 72.3 milivolts</u>

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