Answer:
The initial temperature of the object was 37.6 degrees Celsius
The initial temperature of the object was 37.6 (without units)
Step-by-step explanation:
we have
where
f(t) represent the temperature of the object in degree Celsius
t is the time in minutes
<em>Find the value of the constant C</em>
we have the ordered pair (4,35)
substitute in the equation and solve for C
Find the initial value of the object
we know that
The initial temperature is the value of f(t) when the value of t is equal to zero
so
For t=0
therefore
The initial temperature of the object was 37.6 degrees Celsius
The initial temperature of the object was 37.6 (without units)
Given:
Vertices of a triangular garden:
A(4,2)
B(2,4)
C(6,4)
Scale factor = 0.5
Find the distance between points:
d = √(x2-x1)^2 + (y2-y1)^2
dAB = 2√2
dBC = 4
dCA = 2√2
A similarly shaped garden is to be created using the scale factor, 0.5:
A' = 2√2 / 0.5 = 4√2
B' = 4 / 0.5 = 8
C' = 2√2 / 0.5 = 4√2
Answer:
Cam has a greater balance and Ben has more debt.
Answer:
13 and 27
Step-by-step explanation:
x+y=40
x- smaller
2y-x=41
x=2y-41
Now to plug it into our first equation:
3y-41=40
3y=81
y=27
x=13
Answer:
F(n) = 2n – 2
Step-by-step explanation:
The sequence 0, 2, 4, 6
First, let us determine if the sequence is arithmetic progression (A.P) or geometric progression (G.P)
This is illustrated:
Let us calculate the common difference (d)
Common difference (d) = 2nd term – first term
Common difference (d) = 3rd term – 2nd term
=> 2 – 0 = 2
=> 4 – 2 = 2
The common difference (d) = 2.
Common ratio (r) = 2nd term /1st term
Common ratio (r) = 3rd term /2nd term
=> 2/0 = undefined
=> 4/2 = 2
There is no common ratio.
Since we have a common difference, therefore the sequence is arithmetic progression.
Now, let us obtain an expression for the sequence.
This can be obtained by using the arithmetic progression formula as shown below:
F(n) = a + (n – 1)d
a is the first term
n is the number of term
d is the common difference.
The sequence 0, 2, 4, 6
The first term (a) = 0
Common difference (d) = 2
F(n) = a + (n – 1)d
F(n) = 0 + (n – 1)2
F(n) = 2n – 2
