The answer is D from picture you posted .
Answer:
Therefore you can wear your rings in =336 ways
Step-by-step explanation:
Multiplication Law: If one occurs in x ways and second event occurs in y ways.Then the number of ways that two event occur in sequence is xy
Given that you have 3 different rings.
We have total 10 figures.
But you don't wear ring on your thumbs.
We have 2 thumbs.
So you can wear rings on (10-2) = 8 figures.
The ways of wearing of first ring is = 8
The ways of wearing of second ring is = 7
The ways of wearing of third ring is = 6
Therefore you can wear your rings in =(8×7×6)
=336 ways
I hope this is just a maths problem coz if this is your card number I wouldn't be putting it on here for all to see.
Ayanna is 17 and Brittany is 14.
To find this, let's write two equations using the given information.
a = b + 3
3b + 2a = 76
Now, just substitute the first equation into the second and solve.
3b + 2(b + 3) = 76
3b + 2b + 6 = 76
5b = 70
b = 14
If Brittany is 14, then Ayanna is 3 years older at 17.
2194/10000 using prime factorisation method
