At at least one die come up a 3?We can do this two ways:) The straightforward way is as follows. To get at least one 3, would be consistent with the following three mutually exclusive outcomes:the 1st die is a 3 and the 2nd is not: prob = (1/6)x(5/6)=5/36the 1st die is not a 3 and the 2nd is: prob = (5/6)x((1/6)=5/36both the 1st and 2nd come up 3: prob = (1/6)x(1/6)=1/36sum of the above three cases is prob for at least one 3, p = 11/36ii) A faster way is as follows: prob at least one 3 = 1 - (prob no 3's)The probability to get no 3's is (5/6)x(5/6) = 25/36.So the probability to get at least one 3 is, p = 1 - (25/36) = 11/362) What is the probability that a card drawn at random from an ordinary 52 deck of playing cards is a queen or a heart?There are 4 queens and 13 hearts, so the probability to draw a queen is4/52 and the probability to draw a heart is 13/52. But the probability to draw a queen or a heart is NOT the sum 4/52 + 13/52. This is because drawing a queen and drawing a heart are not mutually exclusive outcomes - the queen of hearts can meet both criteria! The number of cards which meet the criteria of being either a queen or a heart is only 16 - the 4 queens and the 12 remaining hearts which are not a queen. So the probability to draw a queen or a heart is 16/52 = 4/13.3) Five coins are tossed. What is the probability that the number of heads exceeds the number of tails?We can divide
Answer:
Step-by-step explanation:
Answer:
Option C
Step-by-step explanation:
Given that u-ai + bj and v-ci + dj are vectors
We have dot product
hence inner product of u and v. So option a is true
The dot product of u and v is a scalar is true because dot product is always a scalar
The dot product of u and v is a vector. is false because dot product is only a scalar and has no direction and hence cannot be a vector
The dot product of u and v is given by the expression ac+bd
True because we multiply corresponding i components and j components and add.
So only C is not true.
It all depends on the car . what are the answers ?
Answer:
117 cups
Step-by-step explanation:
two dozen cookies calls for 234cups of sugar
2 dozen cookies = 234 cups of sugar
How much sugar is needed to make one dozen cookies?
Let x = cups of sugar needed
1 dozen cookies = x cups of sugar
2 dozen cookies : 234 cups of sugar = 1 dozen cookies : x cups of sugar
2 : 234 = 1 : x
2 / 234 = 1 / x
Cross product
2*x = 234 * 1
2x = 234
x = 234 / 2
= 117 cups
Your options are wrong because none corresponds with the answer
