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3 years ago

A circular sector has a central angle of π6 radians and a radius of 9 ft.

Mathematics

2 answers:

ohaa [14]3 years ago

8 0

Answer:

$\approx \: 21.2 \: {ft}^{2}$

Step-by-step explanation:

$central \: \angle = \frac{\pi ^{c} }{6} = 30 \degree \\ \\ area \: of \: the \: sector = \frac{30 \degree}{360 \degree} \times \pi {(9)}^{2} \\ \\ = \frac{1}{12} \times 3.14 \times 81 \\ \\ = \frac{1}{12} \times 254.34 \\ \\ = 21.195 \: {ft}^{2} \\ \\ \approx \: 21.2 \: {ft}^{2}$

docker41 [41]3 years ago

3 0

Answer:

given

π6radian=30°

radius r =9ft

the area of the sector=30°/360×π×r²

=30/360×22/7×9²=21.214ft²

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Step-by-step explanation:

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Taking sin²θ common in both numerator & denominator, We get :

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$\mathsf{\implies \dfrac{2}{3}}$

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timurjin [86]

Hi!

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-------------------------------\\\\$

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\begin{array}{rllll}
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x&&y
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or using a unit vector for those above, then

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\\\\\\
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