Question

A circular sector has a central angle of π6 radians and a radius of 9 ft.

Answer 1

Answer:

$\approx \: 21.2 \: {ft}^{2}$

Step-by-step explanation:

$central \: \angle = \frac{\pi ^{c} }{6} = 30 \degree \\ \\ area \: of \: the \: sector = \frac{30 \degree}{360 \degree} \times \pi {(9)}^{2} \\ \\ = \frac{1}{12} \times 3.14 \times 81 \\ \\ = \frac{1}{12} \times 254.34 \\ \\ = 21.195 \: {ft}^{2} \\ \\ \approx \: 21.2 \: {ft}^{2}$

Answer 2

Answer:

given

π6radian=30°

radius r =9ft

the area of the sector=30°/360×π×r²

=30/360×22/7×9²=21.214ft²