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12345 [234]
3 years ago
11

A circular sector has a central angle of π6 radians and a radius of 9 ft.

Mathematics
2 answers:
ohaa [14]3 years ago
8 0

Answer:

\approx \: 21.2 \:  {ft}^{2}

Step-by-step explanation:

central \:  \angle   =  \frac{\pi ^{c} }{6}  = 30 \degree \\  \\ area \: of \: the \: sector =  \frac{30 \degree}{360 \degree}  \times \pi {(9)}^{2}  \\  \\  =  \frac{1}{12}  \times 3.14 \times  81 \\  \\  =   \frac{1}{12}  \times 254.34 \\  \\  = 21.195 \:  {ft}^{2}  \\  \\  \approx \: 21.2 \:  {ft}^{2}

docker41 [41]3 years ago
3 0

Answer:

given

π6radian=30°

radius r =9ft

the area of the sector=30°/360×π×r²

=30/360×22/7×9²=21.214ft²

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Explanation:

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The boundary line is included if the symbol includes the "or equal to" condition (≤ or ≥). An included boundary line is graphed as a solid line.

When the inequality symbol does not include the "or equal to" condition (< or >), the boundary line is not included in the solution space, and it is graphed as a dashed line.

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Otherwise, the shaded solution space will be below or to the left of the boundary line.

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Just as a system of linear equations may have no solution, so that may be the case for inequalities. If the boundary lines are parallel and the solution spaces do not overlap, then there is no solution.

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The attached graph shows an example of graphed inequalities. The solutions for this system are in the doubly-shaded area to the left of the point where the lines intersect. We have purposely shown both kinds of inequalities (one "or equal to" and one not) with shading both above and below the boundary lines.

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Answer:

z=\frac{0.659 -0.5}{\sqrt{\frac{0.5(1-0.5)}{502}}}=7.124  

p_v =P(z>7.124)=5.24x10^{-13}  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is significantly higher than 0.5.  

Step-by-step explanation:

Data given and notation

n=502 represent the random sample taken

X=331 represent the adults that said they would not be bothered if the NAtional security agency

\hat p=\frac{331}{502}=0.659 estimated proportion of people who would not be bothered if the NAtional security agency

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than the majority of 0.5:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.659 -0.5}{\sqrt{\frac{0.5(1-0.5)}{502}}}=7.124  

Statistical decision  

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The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>7.124)=5.24x10^{-13}  

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