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Nata [24]
3 years ago
10

In the perfect square x^2+bx+c, why is the relationship between b and c C=(b/2)^2? Would the strategy work even if b is a negati

ve? Also, would it work if b was an odd number? What would happen to c if b was odd?
Mathematics
1 answer:
o-na [289]3 years ago
3 0

Answer:

Step-by-step explanation:

c = (b/2)² because b = 2c

If b is negative, then c = (-b/2)² , and x² - bx + c = (x-c)²

If b is an odd number, then c will be a fraction.

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Answer:

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