![\large\begin{array}{l} \textsf{a) }\mathsf{(f\circ g)(x)}\\\\ =\mathsf{f\big[g(x)\big]}\\\\ =\mathsf{\big[g(x)\big]^2-6\cdot g(x)+2}\\\\ =\mathsf{\big[\sqrt{x}\big]^2-6\sqrt{x}+2}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(f\circ g)(x)=x-6\sqrt{x}+2} \end{array}}\qquad\checkmark \end{array}](https://tex.z-dn.net/?f=%5Clarge%5Cbegin%7Barray%7D%7Bl%7D%20%5Ctextsf%7Ba%29%20%7D%5Cmathsf%7B%28f%5Ccirc%20g%29%28x%29%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7Bf%5Cbig%5Bg%28x%29%5Cbig%5D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Cbig%5Bg%28x%29%5Cbig%5D%5E2-6%5Ccdot%20g%28x%29%2B2%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Cbig%5B%5Csqrt%7Bx%7D%5Cbig%5D%5E2-6%5Csqrt%7Bx%7D%2B2%7D%5C%5C%5C%5C%5C%5C%20%5Ctherefore~~%5Cboxed%7B%5Cbegin%7Barray%7D%7Bc%7D%5Cmathsf%7B%28f%5Ccirc%20g%29%28x%29%3Dx-6%5Csqrt%7Bx%7D%2B2%7D%20%5Cend%7Barray%7D%7D%5Cqquad%5Ccheckmark%20%5Cend%7Barray%7D)
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![\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}](https://tex.z-dn.net/?f=%5Clarge%5Cbegin%7Barray%7D%7Bl%7D%20%5Ctextsf%7Bb%29%20%7D%5Cmathsf%7B%28g%5Ccirc%20f%29%28-2%29%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7Bg%5Cbig%5Bf%28-2%29%5Cbig%5D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7Bf%28-2%29%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7B%28-2%29%5E2-6%5Ccdot%20%28-2%29%2B2%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7B4%2B12%2B2%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7B18%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7B3%5E2%5Ccdot%202%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B3%5Csqrt%7B2%7D%7D%5C%5C%5C%5C%5C%5C%20%5Ctherefore~~%5Cboxed%7B%5Cbegin%7Barray%7D%7Bc%7D%5Cmathsf%7B%28g%5Ccirc%20f%29%28-2%29%3D3%5Csqrt%7B2%7D%7D%20%5Cend%7Barray%7D%7D%5Cqquad%5Ccheckmark%20%5Cend%7Barray%7D)
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Tags: <em>composite function composition evaluate algebra</em>
The description shows a linear relationship and a proportional relationship.
<h3>How to describe the given relationship?</h3>
The given parameters are:
Charger = $15 per game
Customers are not charged to rent bowling shoes.
The statement "Customers are not charged to rent bowling shoes" means that the linear function has no y-intercept
So, the linear function can be represented as
y = Charges * x
This gives
y = 15x
Linear functions that are proportional functions are represented as y = mx
In this case, y = mx represents y = 15x
Hence, the description shows a linear relationship and a proportional relationship.
Read more about proportional relationship at
brainly.com/question/12242745
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Answer:
Step-by-step explanation:
Decrease = 97 - 75 = 22
Percentage of decrease=
= 22.68
= 23%
The property of equality Wade would use to solve the equation StartFraction x Over 6 EndFraction = 3 is multiplication property of equality.
Given:
StartFraction x Over 6 EndFraction = 3
x / 6 = 3
apply multiplication property of equality by crossing multiply
x = 3 × 6
x = 18
check:
x / 6 = 3
18 / 6 = 3
3 = 3
Therefore, the property of equality Wade would use to solve the equation StartFraction x Over 6 EndFraction = 3 is multiplication property of equality.
Learn more about property of equality:
brainly.com/question/1601404
