Answer:
Step-by-step explanation:
a1 = 6
a2 = 10
a3 = 14
The next member of the sequence is 4 more than the current sequence. Therefore d = 4
a1 = 6
d = 4
n = 13
an = a1 + (n - 1)*d
an = 6 + (n - 1)*4
a_13 = 6 + 12*4
a_13 = 6 + 48
a_13 = 54
Play usually continues 7.Qf3+ Ke6 8.Nc3 (see diagram). Black will play 8...Nb4 or 8...Ne7 and follow up with c6, bolstering his pinned knight on d5. If Black plays 8...Nb4, White can force the b4 knight to abandon protection of the d5 knight with 9.a3?! Nxc2+ 10.Kd1 Nxa1 11.Nxd5, sacrificing a rook, but current analysis suggests that the alternatives 9.Qe4, 9.Bb3 and 9.O-O are stronger. White has a strong attack, but it has not been proven yet to be decisive.
Because defence is harder to play than attack in this variation when given short time limits, the Fried Liver is dangerous for Black in over-the-board play, if using a short time control. It is also especially effective against weaker players who may not be able to find the correct defences. Sometimes Black invites White to play the Fried Liver Attack in correspondence chess or in over-the-board games with longer time limits (or no time limit), as the relaxed pace affords Black a better opportunity to refute the White sacrifice.
Answer:
48.2 cm
Step-by-step explanation:
The bottom side of the large triangle has length 78 cm.
The bottom side of the right triangle has length 78 cm/2 = 39 cm.
Now we use the Pythagorean theorem to find the vertical side, the spine.
39² + s² = 62²
s² = 3844 - 1521
s² = 2323
s = 48.2
Answer: 48.2 cm
1) 100 * 40 = 4000 (cm²) the area of rectangle
2) 40 * 30 * 1/2 = 600 (cm²) the area of triangle
3) 4000 + 600 = 4600 (cm²)
Answer: 4600 cm²
Width W = 10, length L = ?
50 = 2L + 2W
2L = 50 - 2*10 => L = 15
area = L*W = 15*10 = 150 sq.ft.
