Well, first off, let's find what is the slope of BC

now, a line perpendicular to that one, will have a negative reciprocal slope, thus

now, we know the slope "m" of AB is -2 then, thus
Its going more horizontal because the slope has you go up 1 and right 4, meaning you are going right more than you are going up
Answer:
78.5 cm^2
Step-by-step explanation:
the circle's diameter is 10cm --> its radius is 5cm
the area of the circle is 5^2 x 3.14 = 78.5cm^2
Answer:
The answer is indeed with Right angles
60%
I pretty sure this is right