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UkoKoshka [18]
3 years ago
15

Can I get help with 1 & 2??

Mathematics
1 answer:
Rashid [163]3 years ago
3 0
A. g(10)= -29
b.f(3)=16
c.h(-2)=-6
d.j(7)=23
e.h(a)=12/a
f. g(b+c)=-3b-3c+1 ...etc I'm bored
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Pleaseeee pleaseee help mee with precal...One root of 2x2 + 8x + c = 0 is r1 = 1 + √5. Find r2.
igomit [66]
If a root is a+√b then another is a-√b    because of quadatic formula



r2=1-√5
6 0
3 years ago
Read 2 more answers
Subtract fraction and simplify if needed
Harrizon [31]
First you need to find the common denominator. both 6 and 7 go in to 42 evenly

multiply 5/6 by 7 to get 35/42
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23/42
6 0
3 years ago
The area of a rectangle is 27 m^2 , and the length of the rectangle is 3 m less than twice the width. Find the dimensions of the
vagabundo [1.1K]
Let L be the length of the rectangle and W be the width. In the problem it is given that L=2W-3. It is also given that the area LW=27. Substituting in the length in terms of width, we have W(2W-3)=27 \\ 2W^2-3W-27=0 \\ (2W-9)(W+3)=0. Using the zero product property, 2W-9=0 \text{ or } W+3=0. Solving these we get the width W=4.5 \text{ or } -3. However, it doesn't make sense for the width to be negative, so the width must be \boxed{4.5 \text{ m}}. From that we can tell the length L=2(4.5)-3=\boxed{6 \text{ m}}. 
3 0
3 years ago
Identify the domain of the graph given. *Don't forget the parenthesis or brackets*​
anzhelika [568]

Answer:

(-4,3)

Step-by-step explanation:

The domain of a function is all of its possible x-values.  In this graph, there is a y-value for every x-value between -4 and 3 except -4 and 3, because there are open dots at those points.  Therefore, the domain is (-4,3).  Use parenthesis because the function is not defined at x=-4 or x=3.

5 0
3 years ago
Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an
marishachu [46]

Answer: x+x^2+x^3+x^4

Step-by-step explanation:

As per given,

Number of wives = x

Number of sacks = x (\text{Number of wives} )= x\times x = x^2

Number of cats = x(\text{Number of sack})= x \times x^2=x^3

Number of kits = x(\text{Number of cats} )=x\times x^3=x^4

Now , the total number of kits, cats, sacks, and wives going to St. Ives = x+x^2+x^3+x^4

Hence, the required ex[pression:  x+x^2+x^3+x^4

5 0
3 years ago
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