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likoan [24]
3 years ago
10

USING ALL MY POINTS PLS HELP ME ;(

Mathematics
1 answer:
Alchen [17]3 years ago
7 0

Answer:

m\angle AED=90\degree

m\angle DAE=53\degree

m\angle BCE= 53\degree

Step-by-step explanation:

ABCD is a rhombus. AC and BD are its diagonals intersecting at point E.

Diagonals of a rhombus bisects at right angles.

\therefore m\angle AED=90\degree

In\: \triangle AED

m\angle DAE=90\degree-m\angle EDA

m\angle DAE=90\degree-37\degree

m\angle DAE=53\degree

\because m\angle BCE= m\angle DAE

(Alternate angles)

\therefore m\angle BCE= 53\degree

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erma4kov [3.2K]

Answer:

∠ACB 107°

Step-by-step explanation:

1.) First, by using straight angle theorem we can determine that ∠CED is equal to 180 - 147 which is 33°.

2.) Next, using alternate interior angles theorem we know that ∠CDE = ∠ABC which is 40°

3.) Then, because of the angle sum theorem we know that all the angles of the triangle must add to 180° and we can therefore solve for ∠DCE using the equation 33 + 40 + x = 180 where x is ∠DCE. By solving this we get 107°.

4.) Finally, using vertical angles theorem we know that ∠DCE = ∠ACB and so ∠ACB is 107°

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Can anyone help me solve ...​
DochEvi [55]

Answer:

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Step-by-step explanation:

Points to keep in mind when solving  triangle problems.

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Answer:

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Step-by-step explanation:

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