All categories

2 years ago

What is the slope of 2x-4y=5

Mathematics

2 answers:

Luba_88 [7]2 years ago

4 0

Answer:

1/2 or .5

Step-by-step explanation:

Hey There!

So the first step of this problem is to get y on one side and everything else on the other side

to do so we use inverse operations

so to get rid of the 2x we subtract 2x from each side

we would end up with -4y=5-2x

now want to get rid of the -4 on the y

to do so we would divide each side by -4

we would end up with

$y=\frac{1}{2}x -\frac{4}{5}$

so we can conclude that the slope is 1/2 or .5

stich3 [128]2 years ago

3 0

The slope is 1/2x and the y intercept is -5/4

You might be interested in

In a manufacturing process, a machine produces bolts that have an average length of 5 inches with a variance of .08. If we rando

xz_007 [3.2K]

Answer:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

And replacing:

$\mu_{\bar X}= 5$

And the deviation:

$\sigma_{\bar X}= \frac{0.283}{\sqrt{5}}= 0.126$

And the distribution is given:

$\bar X \sim N(\mu= 0.08, \sigma= 0.126)$

Step-by-step explanation:

For this case we have the following info given :

$\mu= 5. \sigma^2 =0.08$

And the deviation would be $\sigma = \sqrt{0.08}= 0.283$

For this case we select a sample size of n = 5 and the distirbution for the sample mean would be:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

And replacing:

$\mu_{\bar X}= 5$

And the deviation:

$\sigma_{\bar X}= \frac{0.283}{\sqrt{5}}= 0.126$

And the distribution is given:

$\bar X \sim N(\mu= 0.08, \sigma= 0.126)$

4 0

2 years ago

They 1107 Kids divided by 56 Teams how many kids are in a team

Montano1993 [528]

Answer:

It has to be less than 20 kids per team.

Step-by-step explanation:

Because 1107/56 is 19.767857142.

7 0

2 years ago

Read 2 more answers

In a toy store, the ratio of the number of dolls to teddy bears is 6:7. If the store has 120 dolls, how many teddy bears are the

VMariaS [17]

Dolls : teddy bears
6 : 7

if 120 dolls are equal to 6 portions,
7 portions,
(120/6) * 7
140 teddy bears

6 0

2 years ago

Peter paid $79.80 for renting a tricycle for 6 hours. What was the rate per hour for renting the tricycle? (Input only numeric v

ElenaW [278]

Answer:

13.3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Brewed decaffeinated coffee contains some caffeine. We want to estimate the amount of caffeine in 8 ounce cups of decaf coffee a

rusak2 [61]

Answer:

We would have to take a sample of 62 to achieve this result.

Step-by-step explanation:

Confidence level of 95%.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that the standard deviation in the amount of caffeine in 8 ounces of decaf coffee is known to be 2 mg.

This means that $\sigma = 2$

If we wanted to estimate the true mean amount of caffeine in 8 ounce cups of decaf coffee to within /- 0.5 mg, how large a sample would we have to take to achieve this result?

We would need a sample of n.

n is found when $M = 0.5$ . So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.5 = 1.96\frac{2}{\sqrt{n}}$

$0.5\sqrt{n} = 2*1.96$

Dividing both sides by 0.5

$\sqrt{n} = 4*1.96$

$(\sqrt{n})^2 = (4*1.96)^2$

$n = 61.5$

Rounding up

We would have to take a sample of 62 to achieve this result.

8 0

2 years ago