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2 years ago

URGENT !!!!!!!!! Please answer correctly !!!!! Will be marking Brianliest !!!!!!!!!!!!!!!!

Mathematics

2 answers:

Irina-Kira [14]2 years ago

7 0

Answer:

Step-by-step explanation:

y2-y1/x2-x1

did the equation = 0

umka21 [38]2 years ago

4 0

Answer:

Given points are ( 6, -2 ) and ( 12 , -2 )

Step-by-step explanation:

Slope of line ( m )

y2-y1

---------

x2-x1

= (-2 + 2)/ 12-6

Step-by-step explanation:

the slope is 0

You might be interested in

Which of the following is true for the rational function f(x) = x-4/x^2-16?

8090 [49]

For the answer to the question above asking which of the following is true for the rational function f(x) = x-4/x^2-16?
The answer is
g(x)=2 / x^2-16 
g(x) = 2 /(x+4)(x-4) 

setting the denominator to 0, the vertical asymptotes are x = 4 and x = -4
I hope my answer helped you. Feel free to ask more questions. Have a nice day!

3 0

2 years ago

Please help me with this

shutvik [7]

Answer:

1) 151.29 | 2) 413 km | 3) 75 cm

Step-by-step explanation:

1) 12.3 x 12.3 = 151.29 in

2) 17.5 x 23.6 = 413 km

3) 15 x 5 = 75 cm

4 0

2 years ago

The temperature, H, in °F, of a cup of coffee t hours after it is set out to cool is given by the following equation. H = 70 + 1

Alex73 [517]

Answer:

The temperature a t = 0 is 190 °F

The temperature a t = 1 is 100 °F

The temperature a t = 2 is 77.5 °F

It takes 1.5 hours to take the coffee to cool down to 85°F

It takes 2.293 hours to take the coffee to cool down to 75°F

Step-by-step explanation:

We know that the temperature in °F, of a cup of coffee t hours after it is set out to cool is given by the following equation:

$H(t)=70+120(\frac{1}{4})^t$

a) To find the temperature a t = 0 you need to replace the time in the equation:

$H(0)=70+120(\frac{1}{4})^0\\H(0)=70+120\cdot 1\\H(0) = 70+120\\H(0)=190 \:\°F$

b) To find the temperature after 1 hour you need to:

$H(1)=70+120(\frac{1}{4})^1\\H(1)=70+120(\frac{1}{4})\\H(1) = 70+30\\H(1)=100 \:\°F$

c) To find the temperature after 2 hours you need to:

$H(2)=70+120(\frac{1}{4})^2\\H(2)=70+120(\frac{1}{16})\\H(2) = 70+\frac{15}{2} \\H(2)=77.5 \:\°F$

d) To find the time to take the coffee to cool down $85 \:\°F$ , you need to:

$85 = 70+120(\frac{1}{4})^t\\70+120\left(\frac{1}{4}\right)^t=85\\70+120\left(\frac{1}{4}\right)^t-70=85-70\\120\left(\frac{1}{4}\right)^t=15\\\frac{120\left(\frac{1}{4}\right)^t}{120}=\frac{15}{120}\\\left(\frac{1}{4}\right)^t=\frac{1}{8}$

$\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right)$

$\ln \left(\left(\frac{1}{4}\right)^t\right)=\ln \left(\frac{1}{8}\right)$

$\mathrm{Apply\:log\:rule}=\log _a\left(x^b\right)=b\cdot \log _a\left(x\right)$

$t\ln \left(\frac{1}{4}\right)=\ln \left(\frac{1}{8}\right)$

$t=\frac{\ln \left(\frac{1}{8}\right)}{\ln \left(\frac{1}{4}\right)}\\t=\frac{3}{2} = 1.5 \:hours$

e) To find the time to take the coffee to cool down $75 \:\°F$ , you need to:

$75=70+120\left(\frac{1}{4}\right)^t\\70+120\left(\frac{1}{4}\right)^t=75\\70+120\left(\frac{1}{4}\right)^t-70=75-70\\120\left(\frac{1}{4}\right)^t=5\\\left(\frac{1}{4}\right)^t=\frac{1}{24}$

$\ln \left(\left(\frac{1}{4}\right)^t\right)=\ln \left(\frac{1}{24}\right)\\t\ln \left(\frac{1}{4}\right)=\ln \left(\frac{1}{24}\right)\\t=\frac{\ln \left(24\right)}{2\ln \left(2\right)} \approx = 2.293 \:hours$

3 0

2 years ago

A circle with center at (-2,2) passes through (7,2). Find the circumference and area of the circle in terms of .

Karolina [17]

A=π(4.5)^2
A=π(20.25)
A=63.585 units^2

C=πd
C=(4.5)
C=14.13 units

8 0

2 years ago

Gerard Barrett's job allows him 21 days of paid time off per year. He works 40 hours a week and makes $25 per hour. What is the

kondor19780726 [428]

25X+40=21 so solve that

8 0

2 years ago