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galina1969 [7]
3 years ago
8

Sry this is the last one

Mathematics
2 answers:
KIM [24]3 years ago
8 0
The 2nd one:))))))))
aksik [14]3 years ago
5 0
The second one

this is because he only has the ability to decrease the number of trails
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(b) 1-5 P<br> W<br> I=0+90/1<br> 081=1+0S..<br> 65°<br> f<br> O<br> 32°<br> (c)<br> POE<br> R
Gemiola [76]

Answer:

83°

Step-by-step explanation:

w+32+65=180 [being the sum of triangle]

w=180-97=83°

7 0
2 years ago
A box contains 23 transistors,6 of which are defective. If 6 are selected at random, find the probility that none are defective
ipn [44]
|\Omega|=C(23,6)=\dfrac{23!}{6!17!}=100947\\&#10;|A|=C(17,6)=\dfrac{17!}{6!11!}=12376\\\\&#10;P(A)=\dfrac{12376}{100947}=\dfrac{1768}{14421}
3 0
4 years ago
52m when m=105 explain this to me please
JulsSmile [24]
52m when m= 105
52(105)
5,460

so you plug in the 105  next to the 52 and you multiply it and get 5,460.
i hope this helped

5 0
3 years ago
Read 2 more answers
A credit union loans a member $6,000 for the purchase of a used car. The loan is made for 15 months at an annual simple interest
lina2011 [118]
You will need the Total Loan Cost Formula which is
(I'm having trouble attaching the graphic - I think the problem is with Brainly).

If nothing else, go to this web page.
It has a calculator and the formula.
http://www.1728.org/loanfrm4.htm

I get an answer of  $6,238.70


3 0
3 years ago
A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long
alexdok [17]
Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
tan \alpha = \frac{C}{D}
Similarly we can do for large triangle containing flagpole:
tan \alpha = \frac{A}{B}

We see that these two equations have same left sides. This means that their right sides must also be same:
\frac{C}{D} = \frac{A}{B}
We can solve for A:
CB=AD \\ A= \frac{CB}{D}  \\ A= \frac{6*24}{3}  \\ A=48 ft

Height of flagpole is 48 feet.

8 0
4 years ago
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