Answer:
g(x)= 2|x+3|-3
Step-by-step explanation:
hope it helps
Hello,
If center is (0,0)
x²/a²+y²/b²=1 for a half horizontal axis of a, and a half vertical axis of b
Here
a=2 ==> a²=4
b=8 ==> b²=64
Answer:
D. AC ≅ XZ
Step-by-step explanation:
To prove that two triangles are congruent by the Angle-Side-Angle theorem, both triangles must have two corresponding angles that are congruent to each other in each triangle, and also a corresponding included side in each triangle that are congruent.
Thus, we are given that,
<X ≅ <A and <Z ≅ <C, therefore, what is needed is a corresponding included angle in each triangle that are congruent to each other, which are,
AC and XZ
Therefore, what is needed is:
AC ≅ XZ
7/5 = 14/10 = 28/20
Numerator = x
Denominator = x-4
Add 3 to both:
x +3 / (x-4+3)
x+3 = 14
(x-4 +3) = 10 = x-1 = 10
x = 11
Check:
11 -4 = 7 ( denominator is 4 less than the numerator.)
add 3 to both:
11+3 = 14
7+3 = 10
14/10 reduces to 7/5
The original fraction would be 11/7
Well I don't know how to show work on this one.
50. 2 3/4 is between 2 and 3, three times farther from two than three. Draw a dot in approximately that locations and mark it 2 3/4.
51. 4 1/3 is between 4 and 5, twice as far from five as from four. Draw a dot and mark it 4 1/3.
