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3 years ago

HELP ASAP ILL GIVE BRAINLIST

Mathematics

1 answer:

Lelu [443]3 years ago

4 0

Answer:

16/25 or 64%

Step-by-step explanation:

In this problem we see that 64 out of the 100 students did better on the exams. So, to find the answer we must find the percentage form of 64 out of 100.

Step one:

what exactly is 64 out of 100? Well, in the math world when we see 'out of' we know that means 'divided by'. So, 64 out of 100 is 64/100.

Step two:

now we have to turn 64/100 into a percentage. We know that 1/100 is 1% so lets multiply 1 by 64. 64*1 = 64. This means that 64/100 = 64%.

I'm not 100% sure what form you need your answer in but if you need it in percentage for the answer is 64%. If you need your answer in a fraction form the answer would be 64/100 or 16/25 if we simplify the answer.

I hope this helps!!

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Millie has a box of 1 hundred cubes. She also has a bag of 70 cubes. How many trains of 10 cubes can she makes?

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17 trains of ten cubes

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3 years ago

Read 2 more answers

A garden table and a bench cost $852 combined. The table is $98 less than the bench. What is the cost of the bench?

Citrus2011 [14]

Answer:

Step-by-step explanation:

b=bench

852=b+(b-98) since the table is less than the bench by 98$

852-b=b-98

950-b=b

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3 years ago

An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de

Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

$P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721$

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

$P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have:

$P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528$

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

$P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have

$P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453$

The sum of the probabilities is

$P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981$

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3 years ago

Which of the following statements is NOT true about the graph of a system of

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Answer:

The lines will have one positive y-intercept and one negative y-intercept is NOT true.

Step-by-step explanation:

If a graphed system has infinitely many solutions, that means that the two equations are the exact same. This means that they'll have the same slope, y-intercept, and will share all of the same points. Answer b is the only choice left.

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3 years ago

-3w=-w-6. How many solutions

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There is one solution: w=3

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2 years ago