Recently, the texas junior college teachers association annual conference was held in austin. at the time a taxi ride in austin
was $ 1.75 $1.75 for the first 1 5 15 of a mile and $ 0.25 $0.25 for each additional 1 5 15 of a mile. if the distance from one of the convention hotels to the airport is 5.8 5.8 miles, how much will it cost to take a taxi from that hotel to the airport?
The correct question is <span>Recently, the texas junior college teachers association annual conference was held in austin. at the time a taxi ride in austin was $ 1.75 for the first 1/5 of a mile and $ 0.25 for each additional 1/5 of a mile. if the distance from one of the convention hotels to the airport is 5.8 miles, how much will it cost to take a taxi from that hotel to the airport?
we know that (1/5) miles is equal to 0.20 miles so
for the first 0.20 miles----------> $1.75 </span>Remaining Distance = 5.8 - 0.2 miles = 5.6 miles <span>5.6/(0.2) =28 (this is the number of (1/5)th of a mile after the 1st (1/5)th </span><span>Each of these costs 0.25 dollars </span><span>28*0.25 = 7 dollars
Ok i) The equation for a slope is y= mx + c where m is the gradient and c the y-intercept. Ok so the gradient is the y rise / x run. You have selected -2 to 4. The rise is -2 and the run is 4. -2 / 4 = -0.5. So y = -0.5x - 2
ii) (0, -2)
iii) I think this one number i). Ill do i) here, -0.5
