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Maslowich
3 years ago
8

Please make a polynomial meeting the criteria (MAX POINTS) (WILL MAKE VALID ANSWER BRAINLIEST) 50 pts

Mathematics
1 answer:
Naily [24]3 years ago
7 0

Answer:

-x^4/(x-6)(x+2)(x-1/3)

Step-by-step explanation:

-x^4/(x-6)(x+2)(x-1/3)

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Find the volume of the prism.​
Tomtit [17]

Answer:

4.375cm

Step-by-step explanation:

You have to look at what volume equals Volume= l×w×h so 3/2 × 5/4 × 7/3

5 0
3 years ago
What’s the answer?????
S_A_V [24]
30 units^3 (just count the blocks inside) :)
3 0
3 years ago
Bob has to pack 192 boxes. This morning, he packed 84 boxes in 312 hours. If Bob continues at the same rate, how long will it ta
kondor19780726 [428]

Answer:

51.69 hours (see explanation)

Step-by-step explanation:

This question is simple once you break it down:

84 boxes in 312 hours is a rate, so it can be shown in fraction form:

84 boxes / 312 hours

Now to figure out how long it takes to unpack those 192 boxes, just multiply:

192 x 84/312

(192 x 84) / 312

16128 / 312

Now, just divide the numbers:

16128 ÷ 312 = 51.69 hours

6 0
3 years ago
Read 2 more answers
Passing through (2, - 2) and perpendicular to the line whose equation is y= 5x+2
jonny [76]

Step-by-step explanation:

Hey there!!!

Here,

Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.

The equation of a straight line passing through point is,

(y - y1) = m1(x - x1)

Now, put all values.

(y  + 2) = m1(x - 2)

It is the 1st equation.

Another equation is;

y = 5x +2........(2nd equation).

Now, Comparing it with y = mx + c, we get;

m2=5

As per the condition of perpendicular lines,

m1×m2= -1

m1 × 5 = -1

Therefore, m2= -1/5.

Keeping the value of m1 in 1st equation.

(y + 2) =  \frac{ - 1}{5} (x - 2)

Simplify them.

5(y + 2) =  - x + 2

5y + 10 =  - x + 2

x + 5y + 8 = 0

Therefore the required equation is x+5y+8= 0.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
4 years ago
The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radiu
rjkz [21]

The balloon has a volume V dependent on its radius r:

V(r)=\dfrac43\pi r^3

Differentiating with respect to time t gives

\dfrac{\mathrm dV}{\mathrm dt}=4\pi r^2\dfrac{\mathrm dr}{\mathrm dt}

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

10\dfrac{\mathrm m^3}{\mathrm s}=4\pi (3\,\mathrm m)^2\dfrac{\mathrm dr}{\mathrm dt}\implies\dfrac{\mathrm dr}{\mathrm dt}=\dfrac5{18\pi}\dfrac{\rm m}{\rm s}

The surface area of the balloon is

S(r)=4\pi r^2

and differentiating gives

\dfrac{\mathrm dS}{\mathrm dt}=8\pi r\dfrac{\mathrm dr}{\mathrm dt}

so that at the moment the radius is 3 m, its area is increasing at a rate of

\dfrac{\mathrm dS}{\mathrm dt}=8\pi(3\,\mathrm m)\left(\dfrac5{18\pi}\dfrac{\rm m}{\rm s}\right)=\dfrac{20}3\dfrac{\mathrm m^2}{\rm s}

4 0
3 years ago
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