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Elina [12.6K]
3 years ago
10

When a number is increased by 13, the resultis 43. What equation fits this statement?​

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
6 0

Answer:

30+13=43

Step-by-step explanation:

when you increase 30 by 13 you end up with 43

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Simplify the expression:<br> 8g2–3g2+g2
Olin [163]

Answer:

Transform your question to : 8g2 - 3g2 - 1g2

"We added a 1 to the last g2 and it became 1g2"

So now I'm just gonna give you the answer I got.

8g2 - 3g2 - 1g2

= 4g2

Solution: 4g2

Step-by-step explanation:

Hope it helps!!~

<em>UwU</em>

8 0
3 years ago
What plus what gives you 20 use six
dolphi86 [110]
6 + x = 20
     - 6   - 6
x = 14
14 plus six gives you 20.

4 0
4 years ago
Read 2 more answers
what is the product of 6x – y and 2x – y 2? 8x2 – 4xy 12x y2 – 2y 12x2 – 8xy 12x y2 – 2y 8x2 4xy 4x y2 – 2y 12x2 8xy 4x y2 2y
tekilochka [14]
(6x-y)(2x-y)=12x^{2}-8xy+y^{2}
3 0
3 years ago
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Jasmine purchased a laptop worth $1,500 in 2007. It loses its value by %32 each year. What is the value of the laptop in 2010? R
Lunna [17]

Answer:

$471.65

Step-by-step explanation:

-The value of the laptop after each year is calculated by the formula:

P_t=P_o(1-d)^t

where:

P_t is the value at time t

P_o is the initial value

d is the rate of depreciation

t is the time

#We substitute the values to solve for the value after 3 years(2010-2007=3):

P_t=P_o(1-d)^t\\\\=1500(1-0.32)^3\\\\=\$471.65

Hence, the value of the laptop in 2010 is $471.65

3 0
3 years ago
Determine if the expressions are equivalent: 7+ 7x; 7 x + 1/7
patriot [66]

<u>The given  expressions  7+ 7x ; 7 x + 1/7 are not equivalent or equal </u>

<u>to each other </u>

<u />

<u>Step-by-step explanation:</u>

Let us firstly assume that  7 + 7x is equivalent ( to 7(x + 1/7) so that means

7 + 7x = 7(x + 1/7)

7 + 7x = 7x + 7(1/7)

7 + 7x = 7x + 1

7x + 7 = 7x + 1

Now, subtracting 7x from both sides, we get:

7x - 7x + 7 = 7x - 7x + 1

(7 - 7)x + 7 = (7 - 7)x + 1

(0)x + 7 = (0)x + 1   thus their occurs a  false statement:

7 = 1 ( we know, 7 >1)

Thus we can say that

<u>7 + 7x is NOT equivalent  to 7(x + 1/7)</u>

5 0
3 years ago
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