A farmer harvested 35 acres of corn and 20 acres of beans. Animals ate 18

A sweater is on sale for 20% off. A jacket is on sale for 15% off. The sale price for each item is $34.00. Which item cost more

SashulF [63]

The sweater cost more originally. It costs $2.50 more from jacket.

Step-by-step explanation:

Given,

Discount rate of sweater = 20%

Sale price of sweater = (100-20)% = 80%

Discount rate of jacket = 15%

Sale price of jacket = (100-15)% = 85%

Sale price of each item = $34.00

Let,

x be the original price of sweater.

y be the original price of jacket.

80% of x = 34

$\frac{80}{100}x=34\\0.80x=34$

Dividing both sides by 0.80

$\frac{0.80x}{0.80}=\frac{34}{0.80}\\x=42.50$

The original price of sweater is $42.50

85% of y = 34

$\frac{85}{100}y=34\\0.85y=34$

Dividing both sides by 0.85

$\frac{0.85y}{0.85}=\frac{34}{0.85}\\y=40$

The original cost of jacket is $40

Difference = 42.50 - 40 = $2.50

The sweater cost more originally. It costs $2.50 more from jacket.

Keywords: subtraction, division

Learn more about subtraction at:

#LearnwithBrainly

4 0

3 years ago

Need Answer Fast Please to solve the Linear Expression: 5(5n+2)+(3-2n)

tatyana61 [14]

Answer:

23n +13

Step-by-step explanation:

5(5n+2)+(3-2n)

Distribute

25n + 10 +3 -2n

Combine like terms

25n -2n + 10+3

23n +13

3 0

3 years ago

Read 2 more answers

An aquarium measures 61 cm long, 30.5 cm wide, and 30.5 cm high.If the tank is only filled to 80% capacity with water, how much

LiRa [457]

Answer:

$V=45396.2\ cm^3$

Step-by-step explanation:

Given that,

The dimensions of an aquarium are 61 cm long, 30.5 cm wide, and 30.5 cm high.

The tank is filled to 80% capacity with water.

We need to find the water needed for this tank.

The volume of cuboid is given by :

$V=lbh$

As it is filled to 80% capacity, so,

$V=\dfrac{80}{100}\times lbh\\\\=0.8\times 61\times 30.5\times 30.5\\\\V=45396.2\ cm^3$

So, $45396.2\ cm^3$ of water is needed for this tank.

5 0

2 years ago

COMPLETE

Xelga [282]

It’s obvious. X Delmar practiced more

3 0

3 years ago

Read 2 more answers

A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe

PSYCHO15rus [73]

Answer:

Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2 bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let A = (u - E) * ( $\sqrt{n}$ / s) be the test statistic

we want P( average_l < A < average_u ) = 95%

look for lower 2.5% and the upper 97.5% Because I think this is a 2-tail test

average_l = -1.96 which corresponds to the 2.5%

average_u = 1.96

P( -1.96 < A < 1.96) = 95%

P( -1.96 < (u - E) * ( $\sqrt{n}$ / s) < 1.96) = 95%

Solve for the true mean E ok

E < u + 1.96* (s / $\sqrt{n}$ )

from -1.96 < (u - E) * ( $\sqrt{n}$ / s)

E < 26,226.2 + 1.96*( 2,322.32 / $\sqrt{77}$ )

E < 26,226.2 + 518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s / $\sqrt{n}$ ) < E

26,226.2 - 518.7197348105429466 < E

25,707.48026519 < E

lower bound is 25,707.48026519

Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)

7 0

3 years ago