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WINSTONCH [101]
3 years ago
6

Im just trying to get you out the friend zone

Mathematics
2 answers:
dimaraw [331]3 years ago
4 0

Answer:

WHY

Step-by-step explanation:

navik [9.2K]3 years ago
3 0

Answer:

too bad

Step-by-step explanation:

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Find the distance between (6, -2) and (1, -2).
Scilla [17]

Answer:

it is 5 units

Step-by-step explanation:

All you have to do for this one is subtract 6-1 which equal 5 units. This only works in this one because is says at the end -2 on both the numbers.

8 0
3 years ago
Read the word problem below.
melamori03 [73]
The answer is: if x represents the number of pencils per box, solve the equation 8x+4=196
5 0
2 years ago
Read 2 more answers
an ellipse has a center at the origin , a vertex along the major axis at (13,0), and a focus at (12,0). What is the equation of
-BARSIC- [3]

Answer:

The answer to your question is below

Step-by-step explanation:

Data

Center = (0, 0)

Vertex = (13, 0)

Focus = (12, 0)

Process

From the data we know that it is a horizontal ellipse.

1.- Calculate "a", the distance from the center to the vertex.

                  a = 13

2.- Calculate "c", the distance from the center to the focus

                  c = 12

3.- Calculate b

Use the Pythagorean theorem to find it

                  a² = b² + c²

-Solve for b

                  b² = a² - c²

-Substitution

                  b² = 13² - 12²

-Simplification

                  b² = 169 - 144

                  b² = 25

                  b = 5

4.- Find the equation of the ellipse

                       \frac{x^{2} }{13^{2}} + \frac{y^{2}}{5^{2}} = 1    or \frac{x^{2} }{169} + \frac{y^{2}}{25} = 1

7 0
3 years ago
Which two tables represent the same function?
topjm [15]

Answer:

The 1st and the 5th tables represent the same function

Step-by-step explanation:

* Lets explain how to solve the problem

- There are five tables of functions, two of them are equal

- To find the two equal function lets find their equations

- The form of the equation of a line whose endpoints are (x1 , y1) and

  (x2 , y2) is \frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

* Lets make the equation of each table

# (x1 , y1) = (4 , 8) and (x2 , y2) = (6 , 7)

∵ x1 = 4 , x2 = 6 and y1 = 8 , y2 = 7

∴ \frac{y-8}{x-4}=\frac{7-8}{6-4}

∴ \frac{y-8}{x-4}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 8) = -1(x - 4) ⇒ simplify

∴ 2y - 16 = -x + 4 ⇒ add x and 16 for two sides

∴ x + 2y = 20 ⇒ (1)

# (x1 , y1) = (4 , 5) and (x2 , y2) = (6 , 4)

∵ x1 = 4 , x2 = 6 and y1 = 5 , y2 = 4

∴ \frac{y-5}{x-4}=\frac{4-5}{6-4}

∴ \frac{y-5}{x-4}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 5) = -1(x - 4) ⇒ simplify

∴ 2y - 10 = -x + 4 ⇒ add x and 10 for two sides

∴ x + 2y = 14 ⇒ (2)

# (x1 , y1) = (2 , 8) and (x2 , y2) = (8 , 5)

∵ x1 = 2 , x2 = 8 and y1 = 8 , y2 = 5

∴ \frac{y-8}{x-2}=\frac{5-8}{8-2}

∴ \frac{y-8}{x-2}=\frac{-3}{6}=====\frac{y-8}{x-2}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 8) = -1(x - 2) ⇒ simplify

∴ 2y - 16 = -x + 2 ⇒ add x and 16 for two sides

∴ x + 2y = 18 ⇒ (3)

# (x1 , y1) = (2 , 10) and (x2 , y2) = (6 , 14)

∵ x1 = 2 , x2 = 6 and y1 = 10 , y2 = 14

∴ \frac{y-10}{x-2}=\frac{14-10}{6-2}

∴ \frac{y-10}{x-2}=\frac{4}{4}======\frac{y-10}{x-2}=1

- By using cross multiplication

∴ (y - 10) = (x - 2)

∴ y - 10 = x - 2 ⇒ add 2 and subtract y in the two sides

∴ -8 = x - y ⇒ switch the two sides

∴ x - y = -8 ⇒ (4)

# (x1 , y1) = (2 , 9) and (x2 , y2) = (8 , 6)

∵ x1 = 2 , x2 = 8 and y1 = 9 , y2 = 6

∴ \frac{y-9}{x-2}=\frac{6-9}{8-2}

∴ \frac{y-9}{x-2}=\frac{-3}{6}======\frac{y-9}{x-2}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 9) = -1(x - 2) ⇒ simplify

∴ 2y - 18 = -x + 2 ⇒ add x and 18 for two sides

∴ x + 2y = 20 ⇒ (5)

- Equations (1) and (5) are the same

∴ The 1st and the 5th tables represent the same function

3 0
3 years ago
Geometry help please?
scZoUnD [109]
A) All angles are right angles, opposite sides are parallel, opposite sides are congruent
b) All sides are congruent
c) opposite sides are parallel
d) all sides are congruent
4 0
3 years ago
Read 2 more answers
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