Find the product. (-5a2)3 · a5
1 answer:
Answer:
![-125a^{11}](https://tex.z-dn.net/?f=-125a%5E%7B11%7D)
Step-by-step explanation:
The expression that we have in this problem is
![(-5a^2)^3\cdot a^5](https://tex.z-dn.net/?f=%28-5a%5E2%29%5E3%5Ccdot%20a%5E5)
First of all, we proceed by evaluating the power of the term in the brackets. We apply the rule:
![(a^m)^n=a^{m\cdot n}](https://tex.z-dn.net/?f=%28a%5Em%29%5En%3Da%5E%7Bm%5Ccdot%20n%7D)
So
![(a^2)^3=a^6](https://tex.z-dn.net/?f=%28a%5E2%29%5E3%3Da%5E6)
Moreover, we have
![(-5)^3=-125](https://tex.z-dn.net/?f=%28-5%29%5E3%3D-125)
Therefore,
![(-5a^2)^3=-125 a^6](https://tex.z-dn.net/?f=%28-5a%5E2%29%5E3%3D-125%20a%5E6)
So now the expression is
![-125a^6 \cdot a^5](https://tex.z-dn.net/?f=-125a%5E6%20%5Ccdot%20a%5E5)
Now we apply the following rule:
![a^m \cdot a^n = a^{m+n}](https://tex.z-dn.net/?f=a%5Em%20%5Ccdot%20a%5En%20%3D%20a%5E%7Bm%2Bn%7D)
So we have
![a^6\cdot a^5 = a^{6+5}=a^{11}](https://tex.z-dn.net/?f=a%5E6%5Ccdot%20a%5E5%20%3D%20a%5E%7B6%2B5%7D%3Da%5E%7B11%7D)
Therefore, our expression becomes:
![-125a^6\cdot a^5=-125a^{11}](https://tex.z-dn.net/?f=-125a%5E6%5Ccdot%20a%5E5%3D-125a%5E%7B11%7D)
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How many cups are there? You are missing information.
Yes a negative x a negative ( eg -2 x -3 ) = a positive ( eg 6 )
I think that the MEDIAN is 99.5 (b)
the MEAN is 109.875.
Sorry that I couldn't have been of more help.