Which algebraic expression is a difference with two terms?

Mathematics

1 answer:

shepuryov [24]3 years ago

3 0

Answer:

C. 5y -7 is an algebraic expression difference with two terms.

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Please help it due ASAP <br> Pls SHOW WORKINGS also.

marusya05 [52]

Answer:

Step-by-step explanation:

Angle 5 is equal to angle 8 because the two angles are an alternate interior angle. We already know that angle 7 and 8 are supplementary because it's adjacent to each other on a straight line. So, since angle 5 and 8 is equal to each other, angle 5 is also supplementary to angle 7.

4 0

3 years ago

Jnsxdhcdhcfhbh demdencec ecerfgv yes

MrRissso [65]

Step-by-step explanation:

gvxghhujhggfffffddnnkiouucdss

3 0

3 years ago

Read 2 more answers

7 > z + 18 ≥ 6 please help me!

sp2606 [1]

7 > z + 18 ≥ 6

Subtract 18 from all 3 parts:

7-18 > z +18 -18 ≥ 6-18

-11 > z ≥ -12

5 0

3 years ago

PLEASE HELP ASAP!!!

EleoNora [17]

<span>Part 1:

$(x+1)^2-3(x+2) \\ \\ =x^2+2x+1-3x-6 \\ \\ =x^2-x-5$

option b.

Part 2:
$(5x^3y^{-3})(-6x^4y)\\ \\=5(-6)x^{3+4}y^{-3+1}\\ \\=-30x^7y^{-2}\\ \\=\frac{-30x^7}{y^2}$

option d

Part 3:
$\frac{8+x}{2} - \frac{x+3}{3} =4$

Multiply through by the LCM of 2 and 3 (i.e. 6)
$6\left(\frac{8+x}{2}\right) - 6\left(\frac{x+3}{3}\right) =6(4) \\ \\ 3(8+x)-2(x+3)=24 \\ \\ 24+3x-2x-6=24 \\ \\ x+18=24 \\ \\ x=24-18=6$

option b

Part 4
x^2-3x-8=x+4

$x^2-3x-8=x+4 \\ \\ x^2-3x-x-8-4=0 \\ \\ x^2-4x-12=0 \\ \\ (x-6)(x+2)=0 \\ \\ x=6 \ or \ -2$

option d

Part 5
Joseph is solving the equation x^2+8x-4=0 using the technique completing the square.
x^2+8x-4=0
x^2+8x+?=4+?

In completeing the square method, you divide the coeficient of x by 2, square the result and add to both sides of the equation.

Therefore, he should add 16 to both sides because (8/2)^2=16.

option d.
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5 0

3 years ago

Example 2

Arada [10]

Answer:

y=x-2

Step-by-step explanation:

If you have drawn the graph of $y = x^2 - 3x + 1$ .