Answer:
<em>See explanation</em>
Explanation:
Given
Represent the vertical angle with ![\theta](https://tex.z-dn.net/?f=%5Ctheta)
![\theta = 75](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2075)
The question has incomplete details because the length of the ladder is not given; neither is the distance between the ladder and the wall given.
<em>See attachment for illustration</em>
So, this solution will be based on assumptions.
Represent
- The height from ground to the top of the ladder with y
- The length of the ladder with L
- The distance between the ladder and the wall with x
Carla could solve for y in any of the following ways:
1. Tan formula
![tan \theta = \frac{opp}{adj}](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%5Cfrac%7Bopp%7D%7Badj%7D)
In this case:
![tan \theta = \frac{x}{y}](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%5Cfrac%7Bx%7D%7By%7D)
Multiply both sides by y
![y * tan \theta = \frac{x}{y} * y](https://tex.z-dn.net/?f=y%20%2A%20tan%20%5Ctheta%20%3D%20%5Cfrac%7Bx%7D%7By%7D%20%2A%20y)
![y * tan \theta = x](https://tex.z-dn.net/?f=y%20%2A%20tan%20%5Ctheta%20%3D%20x)
Divide both sides by tan
![y = \frac{x}{tan \theta}](https://tex.z-dn.net/?f=y%20%20%20%3D%20%5Cfrac%7Bx%7D%7Btan%20%5Ctheta%7D)
![y = \frac{x}{tan 75}](https://tex.z-dn.net/?f=y%20%20%20%3D%20%5Cfrac%7Bx%7D%7Btan%2075%7D)
This can be used if the distance (x) between the ladder and the wall is known.
Assume x = 15
![y = \frac{15}{tan 75}](https://tex.z-dn.net/?f=y%20%20%20%3D%20%5Cfrac%7B15%7D%7Btan%2075%7D)
![y = 4.02](https://tex.z-dn.net/?f=y%20%3D%204.02)
2. Cosine formula
![cos \theta = \frac{adj}{hyp}](https://tex.z-dn.net/?f=cos%20%5Ctheta%20%3D%20%5Cfrac%7Badj%7D%7Bhyp%7D)
In this case:
![cos \theta = \frac{y}{L}](https://tex.z-dn.net/?f=cos%20%5Ctheta%20%3D%20%5Cfrac%7By%7D%7BL%7D)
Multiply both sides by L
![L * cos \theta = \frac{y}{L} * L](https://tex.z-dn.net/?f=L%20%2A%20cos%20%5Ctheta%20%3D%20%5Cfrac%7By%7D%7BL%7D%20%2A%20L)
![Lcos \theta = y](https://tex.z-dn.net/?f=Lcos%20%5Ctheta%20%3D%20y)
![y = Lcos \theta](https://tex.z-dn.net/?f=y%20%3D%20Lcos%20%5Ctheta)
![y = Lcos75](https://tex.z-dn.net/?f=y%20%3D%20Lcos75)
This can be used if the length (L) of the ladder is known.
Assume L = 15
![y = 15 * cos75](https://tex.z-dn.net/?f=y%20%3D%2015%20%2A%20cos75)
![y = 3.88](https://tex.z-dn.net/?f=y%20%3D%203.88)
Answer:
Explanation:
Conclusion: Regard for and usage of human rights gives the premise to tranquil and amicable concurrence among people groups with various social and religious foundations. This decent variety of societies and religions improves the all-inclusive importance of human rights at the national and provincial dimensions.
Temperature and density increases from the crust to the core.
Hello. This question is incomplete. The full question is:
What can scientists learn from magnetic striping patterns? Select the three correct answers.
1. the cause of magnetic pole reversals
2. the year the next magnetic reversal will take place
3. the location of ancient faults caused by seismic activity
4. the exact location of the next earthquake along the California coast
5. the direction plates are moving relative to each other
6. the speed of one plate as it subducts below another plate
Answer:
The direction plates are moving relative to each other
The speed of one plate as it subducts below another plate
The location of ancient faults caused by seismic activity
Explanation:
Magnetic striping patterns are very valuable systems for understanding the factors that promote polar variability of the ocean floor. This is because these systems are formed exactly by changes in this polarity, presenting lines (similar to a zebra), which allow scientists to interpret them and have valuable information about the movement of the direction plates towards each other, the speed that a plate reaches the subduz below another plate and the location and old faults that were caused by the existence of seismic activities.
Answer:
B) 12 hours of daylight.
Explanation:
B) 12 hours of daylight.
In near the equator we experience 12 hours of daylight as the equator is situated exactly the halfway in between the two poles. The North pole experiences long daylight in the months, when the North Pole is tilted towards the Sun and shorter daylight when the pole tilted away from the Sun. The reverse is true for the Southern Poles. But this wouldn't have any effects in daylight on the equator.