Find an equation of the line passing through the point (−6,−5) that is parallel to the line y=4/3x−5
1 answer:
Answer:
y = x + 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = x - 5 ← is in slope- intercept form
with slope m =
Parallel lines have equal slopes, thus
y = x + c ← is the partial equation
To find c substitute (- 6, - 5) into the partial equation
- 5 = - 8 + c ⇒ c = - 5 + 8 = 3
y = x + 3 ← equation of parallel line
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Answer:
Domain = ( -∞,∞), {x|x ∈ R}
Range (-∞,2], {y|y ≤ 2}
Vertex (h,k) = (6,2)
Step-by-step explanation:
(Domain / Range) The absolute value expression has a V shape. The range of a negative absolute value expression starts at its vertex and extends to negative infinity.
(Vertex) To find the x coordinate of the vertex, set the inside of the absolute value
x − 6 equal to 0 . In this case, x − 6 = 0 .
x−6=0
Add 6 to both sides of the equation.
x=6
Replace the variable x with 6 in the expression.
y=−1/3⋅|(6)−6|+2
Simplify−1/3⋅|(6)−6|+2.
y=2
The absolute value vertex is ( 6 , 2 ) .
(6,2)
Hope this helps
