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3 years ago

Solve for x: 4(x + 2) = 3(x − 2)A) −2B)−4C) −10D) −14

Mathematics

1 answer:

BARSIC [14]3 years ago

6 0

4(x+2)=3(x-2)

Multiply the first bracket by 4

Multiply the second bracket by 3

4x+8=3x-6

Move 3x to the left hand side, whenever moving a number with a letter the sign changes ( positive 3x to negative 3x)

4x-3x+8=3x-3x-6

x+8=-6

Move positive 8 to the right hand side

x+8-8=-6-8

x=-14

Check answer by using substitution method

Use x=-14 into both of the equations

4(-14+2)=3(-14-2)

-56+8=-42-6

-48=-48

Answer is -14- D)

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20) Use the distributive property to factor the expression. 10xz − 20yz

Paraphin [41]

Answer:

C. 10z(x - 2y)

Step-by-step explanation:

10xz − 20y

Factor the terms

Factors of 10xz = 2 × 5 × x × z

Factors of -20yz = (-1) × 2 × 2 × 5 × y × z

Identify their greatest common factor

The common factors are 2, 5, and z. The greatest common factor is 10z.

Rewrite them with the GCF as a factor

10xz = 10z × x

-20yz = 10z × (-2y)

Replace the terms in the original expression with the factored terms

10xz − 20yz = 10z(x) + 10z(-2y)

Use the distributive property to isolate the greatest common factor

10z(x) + 10z(-2y) = 10z(x - 2y)

3 0

3 years ago

I need help...........

harina [27]

Answer:

Step-by-step explanation:

8 0

3 years ago

Someone help me please

galben [10]

Answer:

∛27 = 3

Step-by-step explanation:

A radical is simply a fractional exponent: $a^{(\frac{m}{n})} = \sqrt[n]{a^{m} }$

Hence, ∛27 = $27^{(\frac{1}{3})}$

Since 27 = 3³, then:

You could rewrite ∛27 as ∛(3)³.

$\sqrt[3]{3^{(3)} } = 3^{[(3)*(\frac{1}{3})]}$

Multiplying the fractional exponents (3 × 1/3) will result in 1 (because 3 is the multiplicative inverse of 1/3). The multiplicative inverse of a number is defined as a number which when multiplied by the original number gives the product as 1.

Therefore, ∛27 = 3.

3 0

2 years ago

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Vector B has x, y, and z components of 3, 7.2,

Temka [501]

Answer:

$\approx 9.0\:\mathrm{units}$

Step-by-step explanation:

The magnitude of 3D vector $\vec{v}$ can be given by the following:

$| \overline{v}| =\sqrt{{v_x}^2+{v_y}^2+{v_z}^2}$

Plugging in given values, we have:

$| \overline{v}|=\sqrt{3^2+7.2^2+4.5^2},\\| \overline{v}| \approx \fbox{$9.0\:\mathrm{units}$}$ .

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2 years ago

Please help me branniest Please explain answer

aksik [14]

The answer is c. Because you subtract 5 from 15 because you are dividing (if you were multiplying you would addition)

8 0

3 years ago

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