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guajiro [1.7K]
3 years ago
11

Alexa gets $100 every week from her parents and earns $25 per hour tutoring. Jenna gets $150 from her parents every week and ear

ns $15 per hour baby-sitting. How many hour per week will they have to work to have the same amount? ​
Mathematics
1 answer:
wolverine [178]3 years ago
3 0

Answer: 5 hours/week

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How do you imagine that you will use statistics in your Pharmacy Technician career?
Sladkaya [172]

Answer:

On the job, you'll use math concepts such as percentages, algebra, ratios and fractions to measure out medication, fill prescriptions and keep tabs on the pharmacy's inventory. It's important for you to understand math concepts in several measurement systems so customers get the correct amount of medication needed.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Please help. I’ll mark you as brainliest if correct!
balu736 [363]

Answer: x= -1, z=2, y= -4

Step-by-step explanation:

System of equations:

-5x - 4y - 3z= 15  +

<u>-10x + 4y + 6z= 6</u>

-15x         + 3z = 21  ------>  3 (-5x + z) = 7.3

-5x + z = 7

now,

-10x + 4y + 6z= 6

2(-5x + z) + 4y + 4z = 6

14 + 4y + 4z = 6

7 + 2y + 2z = 3

2y + 2z= -4

y+z=-2

Now we were using the equation: 20x + 4y + 4z = -28

20x + 4(y+z) = 20x -8= - 28

20 x = -20

x= -1

With this we can find y and z

X=-1

-5x + z = 7

z= 2

y+z=-2

y=-4

Finally we have: x= -1, z=2, y= -4

I hope this can help you.

Thank you

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%20%5Cinfty%20%20%5Cfrac%7B%20%5Csqrt%5B%20%20%5Cscriptsize%5Cphi%
Rasek [7]

With ϕ ≈ 1.61803 the golden ratio, we have 1/ϕ = ϕ - 1, so that

I = \displaystyle \int_0^\infty \frac{\sqrt[\phi]{x} \tan^{-1}(x)}{(1+x^\phi)^2} \, dx = \int_0^\infty \frac{x^{\phi-1} \tan^{-1}(x)}{x (1+x^\phi)^2} \, dx

Replace x \to x^{\frac1\phi} = x^{\phi-1} :

I = \displaystyle \frac1\phi \int_0^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx

Split the integral at x = 1. For the integral over [1, ∞), substitute x \to \frac1x :

\displaystyle \int_1^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx = \int_0^1 \frac{\tan^{-1}(x^{1-\phi})}{\left(1+\frac1x\right)^2} \frac{dx}{x^2} = \int_0^1 \frac{\pi2 - \tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx

The integrals involving tan⁻¹ disappear, and we're left with

I = \displaystyle \frac\pi{2\phi} \int_0^1 \frac{dx}{(1+x)^2} = \boxed{\frac\pi{4\phi}}

8 0
2 years ago
Abele bought a skirt and blouse. The skirt cost $15 more than the blouse. Let b represent the cost of the blouse. Write an algeb
julsineya [31]
S = b + 15

s = skirt
b = blouse

The skirt is $15 more than the blouse

7 0
2 years ago
How to solve for x?
Viktor [21]
Multiply both sides by x so that x will be in the numerator
5 0
3 years ago
Read 2 more answers
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