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olga55 [171]
3 years ago
12

3x-12y = 16 and x-4y = 2 solve using elimination

Mathematics
2 answers:
Rom4ik [11]3 years ago
6 0

Answer:

Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.

Step-by-step explanation:

bazaltina [42]3 years ago
5 0
I agree with the other person
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What value of x will make the given triangles congruent?​
ozzi

Answer:

2

Step-by-step explanation:

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3 years ago
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Which equation can pair with x-y=-2 to create a consistent and dependent system?
MrRissso [65]

See the explanation

<h2>Explanation:</h2>

A system that has one or infinitely many solutions is called <em>consistent. </em>If an equation in a system tells us no new information then the equations of the system are <em>dependent. </em>In other words, to find an equation that creates a consistent and dependent system with the given equation we have to get the same line:

The given line is:

x-y=-2

If we multiply both sides of the equation by a constant we will have the same line when plotting, therefore let's multiply by 3:

3(x-y)=3(-2) \\ \\ 3x-3y=-6

So a system of two linear equation that is consistent and dependent is:

\left \{ {{x-y=-2} \atop {3x-3y=-6}} \right.

<h2>Learn more:</h2>

Graph of lines: brainly.com/question/14434483#

#LearnWithBrainly

3 0
4 years ago
Simplify the expression using the distributive property 2x (x- 9)​
Scrat [10]

Answer:

2x^2-18x

Step-by-step explanation:

4 0
3 years ago
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Horatio is solving the equation -3/4+2/5x=7/20x-1/2. Which equations represent possible ways to begin solving for x? Check all t
trapecia [35]

Answer:

  • 2/5x=7/20x+1/4
  • -3/4=-1/20x-1/2
  • -3/4+1/20x=-1/2

Step-by-step explanation:

If you add 3/4 to both sides of the equation, you get ...

... 2/5x = 7/20x + 1/4 . . . . first choice

If you subtract 2/5x from both sides of the equation, you get ...

... -3/4 = -1/20x -1/2 . . . . third choice

If you subtract 7/20x from both sides of the equation, you get ...

... -3/4 +1/20x = -1/2 . . . . last choice

Choices 2 and 4 are erroneous versions of choices 1 and 3, so do not apply.

4 0
3 years ago
Read 2 more answers
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
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