19 divided by 5 please solve it
2 answers:
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Answer:
47.72% of students scored between 563 and 637 on the exam .
Step-by-step explanation:
The percentage of the students scored between 563 and 637 on the exam
= The percentage of the students scored lower than 637 on the exam -
the percentage of the students scored lower than 563 on the exam.
Since 563 is the mean score of students on the Statistics course, 50% of students scored lower than 563. that is P(x<563)=0.5
P(x<637)=P(z<z*) where z* is the z-statistic of the score 637.
z score can be calculated using the formula
z*= where
- X =637
- M is the mean score (563)
- s is the standard deviation of the score distribution (37)
Then z*= =2
P(z<2)=0.9772, which means that 97.72% of students scored lower than 637 on the exam.
As a Result, 97.72%-50%=47.72% of students scored between 563 and 637 on the exam
Answer:
$ 2,200 for 8%, $ 1,300 for 12%
Step-by-step explanation:
I=PRT
Let Bank 1 be <em>x</em>
332= x (8%) + (3,500-x) 12%
332= x (0.08) + (3,500-x) 0.12 change the percent to decimal
332= 0.08x + 420 - 0.12x
0.04x= 420-332
x=
x= 2,200 (Bank 1)
Bank 2= 3,500-Bank 1
Bank 2= 3,500- 2,200
Bank 2= 1,300